Chemistry Exam > Chemistry Questions > The electronic configuration of four elements...
Start Learning for Free
The electronic configuration of four elements are:
(I) [Kr]5s1
(II) [Rn]5f146d17s2
(III) [Ar]3d104s24p5
(IV) [Ar]3d64s2
(I) [Kr]5s1
(II) [Rn]5f146d17s2
(III) [Ar]3d104s24p5
(IV) [Ar]3d64s2
Consider the following statements:
(i) I shows variable oxidation state
(ii) II is a d-block element
(iii) The compound formed between I and III is covalent
(iv) IV shows single oxidation state
(i) I shows variable oxidation state
(ii) II is a d-block element
(iii) The compound formed between I and III is covalent
(iv) IV shows single oxidation state
Which statement is True(T) or Galse (F):
- a)FTFF
- b)FTFT
- c)FFTF
- d)FFFF
Correct answer is option 'D'. Can you explain this answer?
| FREE This question is part of | Download PDF Attempt this Test |
Verified Answer
The electronic configuration of four elements are:(I) [Kr]5s1(II) [Rn]...
1-it shows only +2 oxidation state- Hence False
2-is an f block element- Hence False
3-the bond formed is ionic because 1 is s block and ot is rb and 3 is a halide- Hence False
4-it is a d block element showing multiple oxidation states- Hence False
2-is an f block element- Hence False
3-the bond formed is ionic because 1 is s block and ot is rb and 3 is a halide- Hence False
4-it is a d block element showing multiple oxidation states- Hence False
Most Upvoted Answer
The electronic configuration of four elements are:(I) [Kr]5s1(II) [Rn]...
Electronic Configuration of Elements and Statements
Electronic Configuration:
(I) [Kr]5s1
(II) [Rn]5f146d17s2
(III) [Ar]3d104s24p5
(IV) [Ar]3d64s2
Statements:
(i) I shows variable oxidation state.
(ii) II is a d-block element.
(iii) The compound formed between I and III is covalent.
(iv) IV shows a single oxidation state.
Answer: FFFF
Explanation:
(i) I shows variable oxidation state: False
Element I has only one valence electron in its outermost shell, which is easily lost to form a cation with a +1 oxidation state. Hence it shows a fixed oxidation state.
(ii) II is a d-block element: False
Element II belongs to the f-block and is a member of the actinide series. It has electrons filling in the 5f orbitals.
(iii) The compound formed between I and III is covalent: False
Element I is a metal and Element III is a non-metal. Hence, the compound formed between them is expected to be ionic and not covalent.
(iv) IV shows a single oxidation state: False
Element IV belongs to the d-block and has electrons filling in the d-orbitals. As a result, it can exhibit variable oxidation states.
Electronic Configuration:
(I) [Kr]5s1
(II) [Rn]5f146d17s2
(III) [Ar]3d104s24p5
(IV) [Ar]3d64s2
Statements:
(i) I shows variable oxidation state.
(ii) II is a d-block element.
(iii) The compound formed between I and III is covalent.
(iv) IV shows a single oxidation state.
Answer: FFFF
Explanation:
(i) I shows variable oxidation state: False
Element I has only one valence electron in its outermost shell, which is easily lost to form a cation with a +1 oxidation state. Hence it shows a fixed oxidation state.
(ii) II is a d-block element: False
Element II belongs to the f-block and is a member of the actinide series. It has electrons filling in the 5f orbitals.
(iii) The compound formed between I and III is covalent: False
Element I is a metal and Element III is a non-metal. Hence, the compound formed between them is expected to be ionic and not covalent.
(iv) IV shows a single oxidation state: False
Element IV belongs to the d-block and has electrons filling in the d-orbitals. As a result, it can exhibit variable oxidation states.
Free Test
FREE
| Start Free Test |
Community Answer
The electronic configuration of four elements are:(I) [Kr]5s1(II) [Rn]...
(1) first show+1 oxidation state because it belongs to alkali metal which gives +1 and -1(rare) oxidation state. (F)
(2) second is f - block elements (Lr) which belongs to Actinide series with 103 atomic no. (F)
(3) in this case first element is rubidium(metal) and second is bromine(non-metal) hence, it these makes ionic bond (as we know ionic bond formed by metal and non-metal). (F)
(4) in last case elements is iron which show+6 oxidation state. (F) hence, option 'd' is correct
(2) second is f - block elements (Lr) which belongs to Actinide series with 103 atomic no. (F)
(3) in this case first element is rubidium(metal) and second is bromine(non-metal) hence, it these makes ionic bond (as we know ionic bond formed by metal and non-metal). (F)
(4) in last case elements is iron which show+6 oxidation state. (F) hence, option 'd' is correct
|
Explore Courses for Chemistry exam
|
|
Similar Chemistry Doubts
The electronic configuration of four elements are:(I) [Kr]5s1(II) [Rn]5f146d17s2(III) [Ar]3d104s24p5(IV) [Ar]3d64s2Consider the following statements:(i) I shows variable oxidation state(ii) II is a d-block element(iii) The compound formed between I and III is covalent(iv) IV shows single oxidation stateWhich statement is True(T) or Galse (F):a)FTFFb)FTFTc)FFTFd)FFFFCorrect answer is option 'D'. Can you explain this answer?
Question Description
The electronic configuration of four elements are:(I) [Kr]5s1(II) [Rn]5f146d17s2(III) [Ar]3d104s24p5(IV) [Ar]3d64s2Consider the following statements:(i) I shows variable oxidation state(ii) II is a d-block element(iii) The compound formed between I and III is covalent(iv) IV shows single oxidation stateWhich statement is True(T) or Galse (F):a)FTFFb)FTFTc)FFTFd)FFFFCorrect answer is option 'D'. Can you explain this answer? for Chemistry 2024 is part of Chemistry preparation. The Question and answers have been prepared according to the Chemistry exam syllabus. Information about The electronic configuration of four elements are:(I) [Kr]5s1(II) [Rn]5f146d17s2(III) [Ar]3d104s24p5(IV) [Ar]3d64s2Consider the following statements:(i) I shows variable oxidation state(ii) II is a d-block element(iii) The compound formed between I and III is covalent(iv) IV shows single oxidation stateWhich statement is True(T) or Galse (F):a)FTFFb)FTFTc)FFTFd)FFFFCorrect answer is option 'D'. Can you explain this answer? covers all topics & solutions for Chemistry 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The electronic configuration of four elements are:(I) [Kr]5s1(II) [Rn]5f146d17s2(III) [Ar]3d104s24p5(IV) [Ar]3d64s2Consider the following statements:(i) I shows variable oxidation state(ii) II is a d-block element(iii) The compound formed between I and III is covalent(iv) IV shows single oxidation stateWhich statement is True(T) or Galse (F):a)FTFFb)FTFTc)FFTFd)FFFFCorrect answer is option 'D'. Can you explain this answer?.
The electronic configuration of four elements are:(I) [Kr]5s1(II) [Rn]5f146d17s2(III) [Ar]3d104s24p5(IV) [Ar]3d64s2Consider the following statements:(i) I shows variable oxidation state(ii) II is a d-block element(iii) The compound formed between I and III is covalent(iv) IV shows single oxidation stateWhich statement is True(T) or Galse (F):a)FTFFb)FTFTc)FFTFd)FFFFCorrect answer is option 'D'. Can you explain this answer? for Chemistry 2024 is part of Chemistry preparation. The Question and answers have been prepared according to the Chemistry exam syllabus. Information about The electronic configuration of four elements are:(I) [Kr]5s1(II) [Rn]5f146d17s2(III) [Ar]3d104s24p5(IV) [Ar]3d64s2Consider the following statements:(i) I shows variable oxidation state(ii) II is a d-block element(iii) The compound formed between I and III is covalent(iv) IV shows single oxidation stateWhich statement is True(T) or Galse (F):a)FTFFb)FTFTc)FFTFd)FFFFCorrect answer is option 'D'. Can you explain this answer? covers all topics & solutions for Chemistry 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The electronic configuration of four elements are:(I) [Kr]5s1(II) [Rn]5f146d17s2(III) [Ar]3d104s24p5(IV) [Ar]3d64s2Consider the following statements:(i) I shows variable oxidation state(ii) II is a d-block element(iii) The compound formed between I and III is covalent(iv) IV shows single oxidation stateWhich statement is True(T) or Galse (F):a)FTFFb)FTFTc)FFTFd)FFFFCorrect answer is option 'D'. Can you explain this answer?.
Solutions for The electronic configuration of four elements are:(I) [Kr]5s1(II) [Rn]5f146d17s2(III) [Ar]3d104s24p5(IV) [Ar]3d64s2Consider the following statements:(i) I shows variable oxidation state(ii) II is a d-block element(iii) The compound formed between I and III is covalent(iv) IV shows single oxidation stateWhich statement is True(T) or Galse (F):a)FTFFb)FTFTc)FFTFd)FFFFCorrect answer is option 'D'. Can you explain this answer? in English & in Hindi are available as part of our courses for Chemistry.
Download more important topics, notes, lectures and mock test series for Chemistry Exam by signing up for free.
Here you can find the meaning of The electronic configuration of four elements are:(I) [Kr]5s1(II) [Rn]5f146d17s2(III) [Ar]3d104s24p5(IV) [Ar]3d64s2Consider the following statements:(i) I shows variable oxidation state(ii) II is a d-block element(iii) The compound formed between I and III is covalent(iv) IV shows single oxidation stateWhich statement is True(T) or Galse (F):a)FTFFb)FTFTc)FFTFd)FFFFCorrect answer is option 'D'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of
The electronic configuration of four elements are:(I) [Kr]5s1(II) [Rn]5f146d17s2(III) [Ar]3d104s24p5(IV) [Ar]3d64s2Consider the following statements:(i) I shows variable oxidation state(ii) II is a d-block element(iii) The compound formed between I and III is covalent(iv) IV shows single oxidation stateWhich statement is True(T) or Galse (F):a)FTFFb)FTFTc)FFTFd)FFFFCorrect answer is option 'D'. Can you explain this answer?, a detailed solution for The electronic configuration of four elements are:(I) [Kr]5s1(II) [Rn]5f146d17s2(III) [Ar]3d104s24p5(IV) [Ar]3d64s2Consider the following statements:(i) I shows variable oxidation state(ii) II is a d-block element(iii) The compound formed between I and III is covalent(iv) IV shows single oxidation stateWhich statement is True(T) or Galse (F):a)FTFFb)FTFTc)FFTFd)FFFFCorrect answer is option 'D'. Can you explain this answer? has been provided alongside types of The electronic configuration of four elements are:(I) [Kr]5s1(II) [Rn]5f146d17s2(III) [Ar]3d104s24p5(IV) [Ar]3d64s2Consider the following statements:(i) I shows variable oxidation state(ii) II is a d-block element(iii) The compound formed between I and III is covalent(iv) IV shows single oxidation stateWhich statement is True(T) or Galse (F):a)FTFFb)FTFTc)FFTFd)FFFFCorrect answer is option 'D'. Can you explain this answer? theory, EduRev gives you an
ample number of questions to practice The electronic configuration of four elements are:(I) [Kr]5s1(II) [Rn]5f146d17s2(III) [Ar]3d104s24p5(IV) [Ar]3d64s2Consider the following statements:(i) I shows variable oxidation state(ii) II is a d-block element(iii) The compound formed between I and III is covalent(iv) IV shows single oxidation stateWhich statement is True(T) or Galse (F):a)FTFFb)FTFTc)FFTFd)FFFFCorrect answer is option 'D'. Can you explain this answer? tests, examples and also practice Chemistry tests.
|
|
Explore Courses for Chemistry exam
|
|
Suggested Free Tests
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
|
© EduRev
|
Education Revolution
|
|
Signup to see your scores
go up within 7 days!
Access 1000+ FREE Docs, Videos and Tests
Takes less than 10 seconds to signup