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Let T be the triangle formed by the straight line 3x + 5y - 45 = 0 and the coordinate axes. Let the circumcircle of T have radius of length L, measured in the same unit as the coordinate axes. Then, the integer closest to L is
Correct answer is '9'. Can you explain this answer?
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Let T be the triangle formed by the straight line 3x + 5y - 45 = 0 and...

In any right triangle, the circumradius is half of the hypotenuse. Here,L=   the length of the hypotenuse = 
Hence, the integer close to L = 9
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Most Upvoted Answer
Let T be the triangle formed by the straight line 3x + 5y - 45 = 0 and...
Given:
- The equation of the straight line is 3x + 5y - 45 = 0.
- The triangle T is formed by this line and the coordinate axes.
- The radius of the circumcircle of T is denoted by L.

To find:
The integer closest to the length of L.

Solution:

Step 1: Find the vertices of the triangle T:
To find the vertices of the triangle T, we need to find the points where the line intersects the coordinate axes.

Intersecting the x-axis:
When y = 0, we can solve the equation 3x + 5y - 45 = 0 to find the x-coordinate of the point of intersection with the x-axis.
3x + 5(0) - 45 = 0
3x - 45 = 0
3x = 45
x = 15

So, the point of intersection with the x-axis is (15, 0).

Intersecting the y-axis:
When x = 0, we can solve the equation 3x + 5y - 45 = 0 to find the y-coordinate of the point of intersection with the y-axis.
3(0) + 5y - 45 = 0
5y - 45 = 0
5y = 45
y = 9

So, the point of intersection with the y-axis is (0, 9).

Step 2: Find the distance between the vertices:
Using the distance formula, we can find the distance between the vertices of the triangle T.

Distance between (15, 0) and (0, 9):
d = √((x2 - x1)^2 + (y2 - y1)^2)
= √((0 - 15)^2 + (9 - 0)^2)
= √(225 + 81)
= √306

So, the distance between the vertices (15, 0) and (0, 9) is √306.

Step 3: Find the radius of the circumcircle:
The radius of the circumcircle of a triangle is given by the formula:
R = (abc) / (4A)

Where a, b, and c are the lengths of the sides of the triangle, and A is the area of the triangle.

In this case, we have a right-angled triangle, so we can use the formula for the area of a right-angled triangle:
A = (1/2) * base * height

The base and height of the triangle T are the distances between the vertices.

Base: The base of the triangle is the distance between (15, 0) and (0, 0), which is 15.

Height: The height of the triangle is the distance between (0, 0) and (0, 9), which is 9.

Area: A = (1/2) * 15 * 9 = 67.5

Radius: R = (15 * √306 * 9) / (4 * 67.5) = (√
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Let T be the triangle formed by the straight line 3x + 5y - 45 = 0 and the coordinate axes. Let the circumcircle of T have radius of length L, measured in the same unit as the coordinate axes. Then, the integer closest to L isCorrect answer is '9'. Can you explain this answer?
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