The area of the triangle can be calculated using
Where r = in radius and R is the Circumradius .
a,b,c are the sides of the right angled triangle with c being the hypotenuse .
or we need use the formulae for
The length of the hypotenuse is twice the Circum radius =c = 2R = 10cm.
In a right angled triangle a
2 + b
2 = c
2The area of the triangle is 1/2*(a)*(b) =area
2 = (1/2*(a)*(b)(/a+b+c)/2) = a+b+10 = ab/2
ab-2a-2b-20 = 0.
(a-2)(b-2) = 24 .
and we know that a
2 + b
2 = c
2. = 100
Now (a-2)(b-2) = 24
24 = 1*24
so a = 3 , b = 26 but 3,26,10 cannot form a right triangle .
24 = 2*12
so a = 4 and b = 14
Now (4,14,10 ) also cannot form a right triangle.
24 = 3*8
so a = 5 and b = 10
Now (5,10,10) also cannot form a right triangle
24 = 4*6
a = 6, b = 8
Now we know that (6, 8, 10) is a right triangle such that 10^2 = 6^2 + 8^2
so we get sides as 6, 8 and 10 cm
Now area = (1/2) × 6 × 8 = 24cm
2