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22320 cal of heat is supplied to 100 g of ice at 0oC If the latent heat of fusion of ice is 80 cal g–1 and latent heat of vaporization of water is 540 cal g–1, the final amount of water thus obtained and its temperature respectively area)8g, 100oCb)100 g, 90oCc)92g, 100oCd)82g, 100oCCorrect answer is option 'C'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about 22320 cal of heat is supplied to 100 g of ice at 0oC If the latent heat of fusion of ice is 80 cal g–1 and latent heat of vaporization of water is 540 cal g–1, the final amount of water thus obtained and its temperature respectively area)8g, 100oCb)100 g, 90oCc)92g, 100oCd)82g, 100oCCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for 22320 cal of heat is supplied to 100 g of ice at 0oC If the latent heat of fusion of ice is 80 cal g–1 and latent heat of vaporization of water is 540 cal g–1, the final amount of water thus obtained and its temperature respectively area)8g, 100oCb)100 g, 90oCc)92g, 100oCd)82g, 100oCCorrect answer is option 'C'. Can you explain this answer?.

Solutions for 22320 cal of heat is supplied to 100 g of ice at 0oC If the latent heat of fusion of ice is 80 cal g–1 and latent heat of vaporization of water is 540 cal g–1, the final amount of water thus obtained and its temperature respectively area)8g, 100oCb)100 g, 90oCc)92g, 100oCd)82g, 100oCCorrect answer is option 'C'. Can you explain this answer? in English & in Hindi are available as part of our courses for JEE. Download more important topics, notes, lectures and mock test series for JEE Exam by signing up for free.

Here you can find the meaning of 22320 cal of heat is supplied to 100 g of ice at 0oC If the latent heat of fusion of ice is 80 cal g–1 and latent heat of vaporization of water is 540 cal g–1, the final amount of water thus obtained and its temperature respectively area)8g, 100oCb)100 g, 90oCc)92g, 100oCd)82g, 100oCCorrect answer is option 'C'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of 22320 cal of heat is supplied to 100 g of ice at 0oC If the latent heat of fusion of ice is 80 cal g–1 and latent heat of vaporization of water is 540 cal g–1, the final amount of water thus obtained and its temperature respectively area)8g, 100oCb)100 g, 90oCc)92g, 100oCd)82g, 100oCCorrect answer is option 'C'. Can you explain this answer?, a detailed solution for 22320 cal of heat is supplied to 100 g of ice at 0oC If the latent heat of fusion of ice is 80 cal g–1 and latent heat of vaporization of water is 540 cal g–1, the final amount of water thus obtained and its temperature respectively area)8g, 100oCb)100 g, 90oCc)92g, 100oCd)82g, 100oCCorrect answer is option 'C'. Can you explain this answer? has been provided alongside types of 22320 cal of heat is supplied to 100 g of ice at 0oC If the latent heat of fusion of ice is 80 cal g–1 and latent heat of vaporization of water is 540 cal g–1, the final amount of water thus obtained and its temperature respectively area)8g, 100oCb)100 g, 90oCc)92g, 100oCd)82g, 100oCCorrect answer is option 'C'. Can you explain this answer? theory, EduRev gives you an ample number of questions to practice 22320 cal of heat is supplied to 100 g of ice at 0oC If the latent heat of fusion of ice is 80 cal g–1 and latent heat of vaporization of water is 540 cal g–1, the final amount of water thus obtained and its temperature respectively area)8g, 100oCb)100 g, 90oCc)92g, 100oCd)82g, 100oCCorrect answer is option 'C'. Can you explain this answer? tests, examples and also practice JEE tests.