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What is the wave number of 4th line in Balmer series of Hydrogen spectrum? (R = 1,09,677cm-1)
- a)24,630cm-1
- b)24,360cm-1
- c)24,365cm-1
- d)24,372cm-1
Correct answer is option 'D'. Can you explain this answer?
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What is the wave number of 4th line in Balmer series of Hydrogen spect...
Balmer Series in Hydrogen Spectrum
The Balmer series in the Hydrogen spectrum consists of the visible lines of Hydrogen. It is named after Johann Balmer, who discovered the formula to calculate the wavelengths of these lines.
The formula for the Balmer series can be written as:
1/λ = R(1/2^2 - 1/n^2)
where λ is the wavelength of the line, R is the Rydberg constant (1.097 x 10^7 m^-1), and n is an integer representing the energy level of the electron.
Wave Number of 4th Line in Balmer Series
To find the wave number of the 4th line in the Balmer series, we can use the above formula and substitute n=6, as the 4th line corresponds to the transition from the 6th energy level to the 2nd energy level.
1/λ = R(1/2^2 - 1/6^2)
1/λ = R(1/4 - 1/36)
1/λ = R(8/36)
1/λ = R(2/9)
λ = 9/2R
The wave number is given by the formula:
Wave number = 1/λ
Substituting the value of λ, we get:
Wave number = 2R/9
Substituting the value of the Rydberg constant, we get:
Wave number = 2 x 1.097 x 10^7 / 9 cm^-1
Wave number = 2.44 x 10^6 cm^-1
Rounding off to the nearest whole number, we get the answer as 24,372 cm^-1.
Therefore, the correct answer is option D, 24,372 cm^-1.
The Balmer series in the Hydrogen spectrum consists of the visible lines of Hydrogen. It is named after Johann Balmer, who discovered the formula to calculate the wavelengths of these lines.
The formula for the Balmer series can be written as:
1/λ = R(1/2^2 - 1/n^2)
where λ is the wavelength of the line, R is the Rydberg constant (1.097 x 10^7 m^-1), and n is an integer representing the energy level of the electron.
Wave Number of 4th Line in Balmer Series
To find the wave number of the 4th line in the Balmer series, we can use the above formula and substitute n=6, as the 4th line corresponds to the transition from the 6th energy level to the 2nd energy level.
1/λ = R(1/2^2 - 1/6^2)
1/λ = R(1/4 - 1/36)
1/λ = R(8/36)
1/λ = R(2/9)
λ = 9/2R
The wave number is given by the formula:
Wave number = 1/λ
Substituting the value of λ, we get:
Wave number = 2R/9
Substituting the value of the Rydberg constant, we get:
Wave number = 2 x 1.097 x 10^7 / 9 cm^-1
Wave number = 2.44 x 10^6 cm^-1
Rounding off to the nearest whole number, we get the answer as 24,372 cm^-1.
Therefore, the correct answer is option D, 24,372 cm^-1.
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What is the wave number of 4th line in Balmer series of Hydrogen spectrum? (R = 1,09,677cm-1)a) 24,630cm-1 b) 24,360cm-1 c) 24,365cm-1 d) 24,372cm-1 Correct answer is option 'D'. Can you explain this answer?
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What is the wave number of 4th line in Balmer series of Hydrogen spectrum? (R = 1,09,677cm-1)a) 24,630cm-1 b) 24,360cm-1 c) 24,365cm-1 d) 24,372cm-1 Correct answer is option 'D'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about What is the wave number of 4th line in Balmer series of Hydrogen spectrum? (R = 1,09,677cm-1)a) 24,630cm-1 b) 24,360cm-1 c) 24,365cm-1 d) 24,372cm-1 Correct answer is option 'D'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for What is the wave number of 4th line in Balmer series of Hydrogen spectrum? (R = 1,09,677cm-1)a) 24,630cm-1 b) 24,360cm-1 c) 24,365cm-1 d) 24,372cm-1 Correct answer is option 'D'. Can you explain this answer?.
What is the wave number of 4th line in Balmer series of Hydrogen spectrum? (R = 1,09,677cm-1)a) 24,630cm-1 b) 24,360cm-1 c) 24,365cm-1 d) 24,372cm-1 Correct answer is option 'D'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about What is the wave number of 4th line in Balmer series of Hydrogen spectrum? (R = 1,09,677cm-1)a) 24,630cm-1 b) 24,360cm-1 c) 24,365cm-1 d) 24,372cm-1 Correct answer is option 'D'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for What is the wave number of 4th line in Balmer series of Hydrogen spectrum? (R = 1,09,677cm-1)a) 24,630cm-1 b) 24,360cm-1 c) 24,365cm-1 d) 24,372cm-1 Correct answer is option 'D'. Can you explain this answer?.
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