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Friedel-Craft’s reaction using MeCl and anhydrous AlCl3 will take place most efficiently with
  • a)
     Benzene
  • b)
    Nitrobenzene
  • c)
    Acetophenone
  • d)
    Toluene
Correct answer is option 'D'. Can you explain this answer?
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Explanation:

Friedel-Craft's acylation is a type of electrophilic aromatic substitution reaction in which an acyl group is introduced onto an aromatic ring. In this reaction, anhydrous aluminum chloride (AlCl3) acts as a Lewis acid catalyst, facilitating the formation of the acylium ion, which then reacts with the aromatic compound.

Efficiency of Friedel-Craft's reaction:

The efficiency of the Friedel-Craft's reaction using MeCl (methyl chloride) and anhydrous AlCl3 depends on the reactivity of the aromatic compound. Toluene is more reactive towards Friedel-Craft's acylation compared to benzene, nitrobenzene, or acetophenone due to its higher electron density.

Reason for choosing toluene:

- Toluene has a methyl group which is an activating group, increasing the electron density on the aromatic ring.
- The increased electron density makes toluene more susceptible to electrophilic attack, leading to a more efficient Friedel-Craft's acylation reaction.
- Benzene, nitrobenzene, and acetophenone are less reactive due to the presence of deactivating groups or lack of activating groups.

Therefore, the Friedel-Craft's reaction using MeCl and anhydrous AlCl3 will take place most efficiently with toluene among the given options.
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The plot given below shows P-T curves (where P is the pressure and T is the temperatur e) for two solvents X and Y and isomolal solutions of NaCl in these solvents. NaCl completely dissociates in both the solvents.On addition of equal number of moles of a non-volatile solute S in equal amount (in kg) of these solvents, the elevation of boiling point of solvent X is three times that of solvent Y. Solute S is known to undergo dimerization in these solvents. If the degree of dimerization is 0.7 in solvent Y, the degree of dimerization in solvent X is ______.Treatment of benzene with CO/HCl in the presence of anhydrous AlCl3/CuCl followed by reaction with Ac2O/NaOAc gives compound X as the major product. Compound X upon reaction with Br2/Na2CO3, followed by heating at 473 K with moist KOH furnishes Y as the major product. Reaction of X with H2/Pd-C, followed by H3PO4 treatment gives Z as the major product. Correct answer is '0.05'. Can you explain this answer?

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Friedel-Craft’s reaction using MeCl and anhydrous AlCl3 will take place most efficiently witha)Benzeneb)Nitrobenzenec)Acetophenoned)TolueneCorrect answer is option 'D'. Can you explain this answer?
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Friedel-Craft’s reaction using MeCl and anhydrous AlCl3 will take place most efficiently witha)Benzeneb)Nitrobenzenec)Acetophenoned)TolueneCorrect answer is option 'D'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about Friedel-Craft’s reaction using MeCl and anhydrous AlCl3 will take place most efficiently witha)Benzeneb)Nitrobenzenec)Acetophenoned)TolueneCorrect answer is option 'D'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Friedel-Craft’s reaction using MeCl and anhydrous AlCl3 will take place most efficiently witha)Benzeneb)Nitrobenzenec)Acetophenoned)TolueneCorrect answer is option 'D'. Can you explain this answer?.
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