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In the brown ring complex [Fe(H2O)5(NO)]SO4, nitric oxide behaves as
- a)NO+
- b)neutral NO molecule
- c)NO–
- d)NO2–
Correct answer is option 'A'. Can you explain this answer?
Most Upvoted Answer
In the brown ring complex [Fe(H2O)5(NO)]SO4, nitric oxide behaves asa)...
‘NO’ ligand when attached to Fe behaves as positively charged ligand.
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In the brown ring complex [Fe(H2O)5(NO)]SO4, nitric oxide behaves asa)...
Behavior of nitric oxide in the brown ring complex:
Nitric oxide behaves as NO+ in the brown ring complex [Fe(H2O)5(NO)]SO4. Let's break down the reasons behind this behavior:
Coordination of nitric oxide:
- In the complex, nitric oxide (NO) acts as a ligand coordinating to the central iron atom.
- Nitric oxide donates its lone pair of electrons to form a coordinate covalent bond with the iron atom.
Charge of the complex:
- The overall complex has a positive charge due to the presence of the NO+ ligand.
- This positive charge is balanced by the sulfate (SO4) anion in the complex.
Stability of NO+:
- Nitric oxide (NO) can exist in different oxidation states, including NO+ and NO-.
- In the brown ring complex, NO behaves as NO+ due to the coordination with the iron atom and the resulting charge distribution in the complex.
Conclusion:
- In the brown ring complex [Fe(H2O)5(NO)]SO4, nitric oxide behaves as NO+ by coordinating to the central iron atom and contributing to the overall positive charge of the complex. This behavior is crucial for the stability and properties of the complex.
Nitric oxide behaves as NO+ in the brown ring complex [Fe(H2O)5(NO)]SO4. Let's break down the reasons behind this behavior:
Coordination of nitric oxide:
- In the complex, nitric oxide (NO) acts as a ligand coordinating to the central iron atom.
- Nitric oxide donates its lone pair of electrons to form a coordinate covalent bond with the iron atom.
Charge of the complex:
- The overall complex has a positive charge due to the presence of the NO+ ligand.
- This positive charge is balanced by the sulfate (SO4) anion in the complex.
Stability of NO+:
- Nitric oxide (NO) can exist in different oxidation states, including NO+ and NO-.
- In the brown ring complex, NO behaves as NO+ due to the coordination with the iron atom and the resulting charge distribution in the complex.
Conclusion:
- In the brown ring complex [Fe(H2O)5(NO)]SO4, nitric oxide behaves as NO+ by coordinating to the central iron atom and contributing to the overall positive charge of the complex. This behavior is crucial for the stability and properties of the complex.
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In the brown ring complex [Fe(H2O)5(NO)]SO4, nitric oxide behaves asa)NO+b)neutral NO moleculec)NO–d)NO2–Correct answer is option 'A'. Can you explain this answer? for JEE 2025 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about In the brown ring complex [Fe(H2O)5(NO)]SO4, nitric oxide behaves asa)NO+b)neutral NO moleculec)NO–d)NO2–Correct answer is option 'A'. Can you explain this answer? covers all topics & solutions for JEE 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for In the brown ring complex [Fe(H2O)5(NO)]SO4, nitric oxide behaves asa)NO+b)neutral NO moleculec)NO–d)NO2–Correct answer is option 'A'. Can you explain this answer?.
In the brown ring complex [Fe(H2O)5(NO)]SO4, nitric oxide behaves asa)NO+b)neutral NO moleculec)NO–d)NO2–Correct answer is option 'A'. Can you explain this answer? for JEE 2025 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about In the brown ring complex [Fe(H2O)5(NO)]SO4, nitric oxide behaves asa)NO+b)neutral NO moleculec)NO–d)NO2–Correct answer is option 'A'. Can you explain this answer? covers all topics & solutions for JEE 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for In the brown ring complex [Fe(H2O)5(NO)]SO4, nitric oxide behaves asa)NO+b)neutral NO moleculec)NO–d)NO2–Correct answer is option 'A'. Can you explain this answer?.
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