X square minus (x plus 2 ) (X 3 ) divided / 7 x 1 is equal to 2/ 3...
Explanation:
Simplifying the given expression:
To begin with, we need to simplify the given expression as follows:
X² - (x + 2) (x - 3) / (7x - 1) = 2/3
X² - (x² - x - 6) / (7x - 1) = 2/3
Multiplying both sides by (7x - 1):
(7x - 1) X² - (x² - x - 6) = (2/3) (7x - 1)
7x³ - x² - 6x - 2 = 14x/3 - 2/3
Multiplying both sides by 3:
21x³ - 3x² - 18x - 6 = 14x - 2
21x³ - 3x² - 32x + 4 = 0
Factoring the equation:
Now we need to factor the equation to find the values of x that satisfy it.
21x³ - 3x² - 32x + 4 = 0
3(7x² - x - 2) (x - 2) = 0
We can solve for x by using the Zero Product Property:
7x² - x - 2 = 0 or x - 2 = 0
Solving the first equation using quadratic formula, we get:
x = (1 ± √(1 + 4(7)(2))) / (2(7))
x = (1 ± √(57)) / 14
Therefore, the solutions to the equation are:
x = (1 + √(57)) / 14 or x = (1 - √(57)) / 14 or x = 2
However, we need to check if these values make the denominator zero. If they do, they are not valid solutions.
Checking for valid solutions:
Checking for x = (1 + √(57)) / 14:
7x - 1 = 7(1 + √(57)) / 14 - 1 = (√(57) + 6) / 2
Since this is not equal to zero, x = (1 + √(57)) / 14 is a valid solution.
Checking for x = (1 - √(57)) / 14:
7x - 1 = 7(1 - √(57)) / 14 - 1 = (-√(57) + 6) / 2
Since this is not equal to zero, x = (1 - √(57)) / 14 is also a valid solution.
Checking for x = 2:
7x - 1 = 7(2) - 1 = 13
Since this is not equal to zero, x = 2 is also a valid solution.
Therefore, the solutions to the equation are:
x = (1 + √(57)) / 14, x = (1 - √(57)) / 14, and x = 2.