Equal weights of CH4 and H2 are mixed in an empty container at 25oC. T...
Let equal weights be w g.
Partial pressure = mole fraction × Total pressure
PH2 = 8/9 x Total pressure
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Equal weights of CH4 and H2 are mixed in an empty container at 25oC. T...
Given:
- Equal weights of CH4 and H2 are mixed in an empty container at 25°C.
To find:
- The fraction of the total pressure exerted by H2.
Solution:
1. Calculate the moles of each gas:
- Since the weights of CH4 and H2 are equal, we can assume that they have the same mass.
- The molar mass of CH4 (methane) is 16 g/mol, and the molar mass of H2 (hydrogen) is 2 g/mol.
- Therefore, the moles of CH4 and H2 will be the same when equal weights are taken.
2. Calculate the partial pressures of each gas:
- According to Dalton's law of partial pressures, the total pressure exerted by a mixture of gases is equal to the sum of the partial pressures of each gas.
- The partial pressure of a gas can be calculated using Dalton's law as the product of the mole fraction and the total pressure.
- Since the moles of CH4 and H2 are the same, their mole fractions will also be the same.
- Therefore, the mole fraction of H2 will be 1/2, and the mole fraction of CH4 will also be 1/2.
- Let the total pressure be P. The partial pressure of H2 will be (1/2)P, and the partial pressure of CH4 will also be (1/2)P.
3. Calculate the fraction of the total pressure exerted by H2:
- The fraction of the total pressure exerted by H2 can be calculated as the partial pressure of H2 divided by the total pressure.
- Therefore, the fraction of the total pressure exerted by H2 will be ((1/2)P)/P = 1/2.
Answer:
- The fraction of the total pressure exerted by H2 is 1/2 (option B).