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A smooth rodPQrotates in a horizontal plane about its mid pointMwhich ish= 0.1mvertically below a fixed pointAat a constant angular velocity 14rad/s. A light elastic string of natural length 0.1mforce constant 1.47N/cmhas one end fixed atAand its other end attached to a ring of massm= 0.3kgwhich is free to slide along the rod. When the ring is stationary relative to rod, then which of following is correct.a)Tension in spring is 4.9Nb)Inclination of string with vertical is cos–1(3/5)c)Inclination of string with vertical is cos–1(2/5)d)Tension in spring is 9.8NCorrect answer is option 'B,D'. Can you explain this answer? for Physics 2024 is part of Physics preparation. The Question and answers have been prepared according to the Physics exam syllabus. Information about A smooth rodPQrotates in a horizontal plane about its mid pointMwhich ish= 0.1mvertically below a fixed pointAat a constant angular velocity 14rad/s. A light elastic string of natural length 0.1mforce constant 1.47N/cmhas one end fixed atAand its other end attached to a ring of massm= 0.3kgwhich is free to slide along the rod. When the ring is stationary relative to rod, then which of following is correct.a)Tension in spring is 4.9Nb)Inclination of string with vertical is cos–1(3/5)c)Inclination of string with vertical is cos–1(2/5)d)Tension in spring is 9.8NCorrect answer is option 'B,D'. Can you explain this answer? covers all topics & solutions for Physics 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A smooth rodPQrotates in a horizontal plane about its mid pointMwhich ish= 0.1mvertically below a fixed pointAat a constant angular velocity 14rad/s. A light elastic string of natural length 0.1mforce constant 1.47N/cmhas one end fixed atAand its other end attached to a ring of massm= 0.3kgwhich is free to slide along the rod. When the ring is stationary relative to rod, then which of following is correct.a)Tension in spring is 4.9Nb)Inclination of string with vertical is cos–1(3/5)c)Inclination of string with vertical is cos–1(2/5)d)Tension in spring is 9.8NCorrect answer is option 'B,D'. Can you explain this answer?.

Solutions for A smooth rodPQrotates in a horizontal plane about its mid pointMwhich ish= 0.1mvertically below a fixed pointAat a constant angular velocity 14rad/s. A light elastic string of natural length 0.1mforce constant 1.47N/cmhas one end fixed atAand its other end attached to a ring of massm= 0.3kgwhich is free to slide along the rod. When the ring is stationary relative to rod, then which of following is correct.a)Tension in spring is 4.9Nb)Inclination of string with vertical is cos–1(3/5)c)Inclination of string with vertical is cos–1(2/5)d)Tension in spring is 9.8NCorrect answer is option 'B,D'. Can you explain this answer? in English & in Hindi are available as part of our courses for Physics. Download more important topics, notes, lectures and mock test series for Physics Exam by signing up for free.

Here you can find the meaning of A smooth rodPQrotates in a horizontal plane about its mid pointMwhich ish= 0.1mvertically below a fixed pointAat a constant angular velocity 14rad/s. A light elastic string of natural length 0.1mforce constant 1.47N/cmhas one end fixed atAand its other end attached to a ring of massm= 0.3kgwhich is free to slide along the rod. When the ring is stationary relative to rod, then which of following is correct.a)Tension in spring is 4.9Nb)Inclination of string with vertical is cos–1(3/5)c)Inclination of string with vertical is cos–1(2/5)d)Tension in spring is 9.8NCorrect answer is option 'B,D'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of A smooth rodPQrotates in a horizontal plane about its mid pointMwhich ish= 0.1mvertically below a fixed pointAat a constant angular velocity 14rad/s. A light elastic string of natural length 0.1mforce constant 1.47N/cmhas one end fixed atAand its other end attached to a ring of massm= 0.3kgwhich is free to slide along the rod. When the ring is stationary relative to rod, then which of following is correct.a)Tension in spring is 4.9Nb)Inclination of string with vertical is cos–1(3/5)c)Inclination of string with vertical is cos–1(2/5)d)Tension in spring is 9.8NCorrect answer is option 'B,D'. Can you explain this answer?, a detailed solution for A smooth rodPQrotates in a horizontal plane about its mid pointMwhich ish= 0.1mvertically below a fixed pointAat a constant angular velocity 14rad/s. A light elastic string of natural length 0.1mforce constant 1.47N/cmhas one end fixed atAand its other end attached to a ring of massm= 0.3kgwhich is free to slide along the rod. When the ring is stationary relative to rod, then which of following is correct.a)Tension in spring is 4.9Nb)Inclination of string with vertical is cos–1(3/5)c)Inclination of string with vertical is cos–1(2/5)d)Tension in spring is 9.8NCorrect answer is option 'B,D'. Can you explain this answer? has been provided alongside types of A smooth rodPQrotates in a horizontal plane about its mid pointMwhich ish= 0.1mvertically below a fixed pointAat a constant angular velocity 14rad/s. A light elastic string of natural length 0.1mforce constant 1.47N/cmhas one end fixed atAand its other end attached to a ring of massm= 0.3kgwhich is free to slide along the rod. When the ring is stationary relative to rod, then which of following is correct.a)Tension in spring is 4.9Nb)Inclination of string with vertical is cos–1(3/5)c)Inclination of string with vertical is cos–1(2/5)d)Tension in spring is 9.8NCorrect answer is option 'B,D'. Can you explain this answer? theory, EduRev gives you an ample number of questions to practice A smooth rodPQrotates in a horizontal plane about its mid pointMwhich ish= 0.1mvertically below a fixed pointAat a constant angular velocity 14rad/s. A light elastic string of natural length 0.1mforce constant 1.47N/cmhas one end fixed atAand its other end attached to a ring of massm= 0.3kgwhich is free to slide along the rod. When the ring is stationary relative to rod, then which of following is correct.a)Tension in spring is 4.9Nb)Inclination of string with vertical is cos–1(3/5)c)Inclination of string with vertical is cos–1(2/5)d)Tension in spring is 9.8NCorrect answer is option 'B,D'. Can you explain this answer? tests, examples and also practice Physics tests.