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The energy of an electron in first Bohr orbit of H – atom is – 13.6 eV. The possible energy value of electron in the excited state of Li2+ is
  • a)
    – 122.4 eV
  • b)
    30.6 eV
  • c)
    – 30.6 eV
  • d)
    13.6 eV
Correct answer is option 'C'. Can you explain this answer?
Verified Answer
The energy of an electron in first Bohr orbit of H – atom is &nd...
For the excited state, n = 2 and for Li++ ion, z = 3
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The energy of an electron in first Bohr orbit of H – atom is &nd...
The energy of an electron in the first Bohr orbit of a hydrogen atom can be calculated using the following formula:

E = -13.6 eV / n^2

Where E is the energy of the electron, -13.6 eV is the ionization energy of hydrogen, and n is the principal quantum number.

For the first Bohr orbit, n = 1. Plugging this value into the formula, we get:

E = -13.6 eV / 1^2
= -13.6 eV

Therefore, the energy of an electron in the first Bohr orbit of a hydrogen atom is -13.6 eV.
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The energy of an electron in first Bohr orbit of H – atom is – 13.6 eV. The possible energy value of electron in the excited state of Li2+ isa)– 122.4 eVb)30.6 eVc)– 30.6 eVd)13.6 eVCorrect answer is option 'C'. Can you explain this answer? for 2025 is part of preparation. The Question and answers have been prepared according to the exam syllabus. Information about The energy of an electron in first Bohr orbit of H – atom is – 13.6 eV. The possible energy value of electron in the excited state of Li2+ isa)– 122.4 eVb)30.6 eVc)– 30.6 eVd)13.6 eVCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The energy of an electron in first Bohr orbit of H – atom is – 13.6 eV. The possible energy value of electron in the excited state of Li2+ isa)– 122.4 eVb)30.6 eVc)– 30.6 eVd)13.6 eVCorrect answer is option 'C'. Can you explain this answer?.
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