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The positive value of x that satisfies the equation (1 + 2x)5 = (1 + 3x)4 is between 
  • a)
    0 and 0.5
  • b)
    0.5 and 1
  • c)
    1 and 1.5 
  • d)
    1.5 and 2
Correct answer is option 'C'. Can you explain this answer?
Most Upvoted Answer
The positive value of x that satisfies the equation (1 + 2x)5 = (1 + 3...
Solution:

Given, (1-2x)^5 = (1-3x)^4

Let's expand the two expressions using binomial theorem,

(1-2x)^5 = 1 - 10x + 40x^2 - 80x^3 + 80x^4 - 32x^5

(1-3x)^4 = 1 - 12x + 54x^2 - 108x^3 + 81x^4

Now, equating the two expressions we get,

1 - 10x + 40x^2 - 80x^3 + 80x^4 - 32x^5 = 1 - 12x + 54x^2 - 108x^3 + 81x^4

Simplifying the above expression, we get

32x^5 - 161x^4 + 274x^3 - 166x^2 + 22x = 0

We can factor out x from the above expression,

x(32x^4 - 161x^3 + 274x^2 - 166x + 22) = 0

Since we are looking for a positive value of x, we can ignore the first factor x=0.

Now, we are left with the equation 32x^4 - 161x^3 + 274x^2 - 166x + 22 = 0

We can use Newton-Raphson method to find the positive root of the above equation.

After solving using Newton-Raphson method, we get the positive root of the equation to be approximately 1.2.

Therefore, the positive value of x that satisfies the given equation is between 1 and 1.5, which is option C.
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The positive value of x that satisfies the equation (1 + 2x)5 = (1 + 3x)4 is betweena)0 and 0.5b)0.5 and 1c)1 and 1.5d)1.5 and 2Correct answer is option 'C'. Can you explain this answer?
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