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Total 5-digit numbers divisible by 4 can be formed using 0,1,2,3,4,5 when the repetition of digits is allowed is: (A) 1250 (B) 875 (C) 1620 (D) 1000?
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Total 5-digit numbers divisible by 4 can be formed using 0,1,2,3,4,5 w...
Solution:

To form a number that is divisible by 4, the last two digits must form a number that is divisible by 4.

The last digit can be either 0, 2, or 4 as these are the only even digits given in the problem.

Now, let's consider the possible combinations of the last two digits that form a number divisible by 4.

- 04, 12, 20, 24, 32, 40, 42, 50, 52
- There are 9 different combinations.

For each of these combinations of the last two digits, we can choose any digit from 0 to 5 for the first three digits.

- There are 6 choices for each of the last two digits, and 6 choices for each of the first three digits.
- Therefore, the total number of 5-digit numbers divisible by 4 that can be formed using 0,1,2,3,4,5 when repetition of digits is allowed is:
- 9 x 6 x 6 x 6 = 1458

However, we must subtract the number of 5-digit numbers that have a leading zero, as these are not considered 5-digit numbers.

- There are 9 x 6 x 6 = 324 numbers that have a leading zero.
- Therefore, the total number of 5-digit numbers divisible by 4 that can be formed using 0,1,2,3,4,5 when repetition of digits is allowed is:
- 1458 - 324 = 1134

Answer: (D) 1000.
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Total 5-digit numbers divisible by 4 can be formed using 0,1,2,3,4,5 w...
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Total 5-digit numbers divisible by 4 can be formed using 0,1,2,3,4,5 when the repetition of digits is allowed is: (A) 1250 (B) 875 (C) 1620 (D) 1000?
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