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if x + 1/x = 2cosθ, then for any integer n , xn + 1/xn
  • a)
    2 cos nθ
  • b)
    2 sin nθ
  • c)
    2i cos nθ
  • d)
    2i sin nθ
Correct answer is option 'A'. Can you explain this answer?
Verified Answer
if x + 1/x = 2cosθ, then for any integer n , xn+ 1/xna)2 cos n&t...
x + 1/x = 2cosθ
Let x = cos θ + 1 sin θ
1/x = cosθ − 1sinθ
thus, xn + 1/xn = 2 cos nθ
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if x + 1/x = 2cosθ, then for any integer n , xn+ 1/xna)2 cos n&t...
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if x + 1/x = 2cosθ, then for any integer n , xn+ 1/xna)2 cos n&t...
To solve the equation x * 1/x = 2cos, we can simplify the left side:

x * 1/x = 1.

Therefore, the equation becomes:

1 = 2cos.

To solve for cos, we divide both sides by 2:

cos = 1/2.

This means that the equation is satisfied when the angle whose cosine is 1/2 is substituted for x.
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if x + 1/x = 2cosθ, then for any integer n , xn+ 1/xna)2 cos nθb)2 sinnθc)2i cos nθd)2i sinnθCorrect answer is option 'A'. Can you explain this answer?
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