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What is the least number which when divided by 2, 5, 7 and 9 leaves a remainder of 1 in each case?
  • a)
    631
  • b)
    156
  • c)
    361
  • d)
    147
Correct answer is option 'A'. Can you explain this answer?
Verified Answer
What is the least number which when divided by 2, 5, 7 and 9 leaves a ...
LCM (2, 5, 7, 9 ) = 630
The smallest number which leaves remainder 1 when divided by 2, 5, 7, and 9
= 630+1 = 631
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Most Upvoted Answer
What is the least number which when divided by 2, 5, 7 and 9 leaves a ...
To find the least number that satisfies the given conditions, we need to find the least common multiple (LCM) of the numbers 2, 5, 7, and 9.

- LCM of 2 and 5: The LCM of 2 and 5 is 10, as both numbers are prime and not divisible by each other.
- LCM of 10 and 7: The LCM of 10 and 7 is 70, as 70 is the smallest number divisible by both 10 and 7.
- LCM of 70 and 9: To find the LCM of 70 and 9, we can break down both numbers into their prime factors:
- 70 = 2 * 5 * 7
- 9 = 3 * 3
- LCM = 2 * 3 * 3 * 5 * 7 = 630
- However, we need to find the least number that leaves a remainder of 1 when divided by 2, 5, 7, and 9. So, we add 1 to the LCM: 630 + 1 = 631.

Therefore, the least number that satisfies the given conditions is 631.
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What is the least number which when divided by 2, 5, 7 and 9 leaves a remainder of 1 in each case?a)631b)156c)361d)147Correct answer is option 'A'. Can you explain this answer?
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