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A quantity of gas is compressed according to pv^n= constant the initial pressure and volume being 1.03bar and .98m^3 respectively. The temperature at the start of compression is 17 degree Celsius and at the end it is 115 degree Celsius. The amount of heat rejected during compression is 3.78KJ and cp=.92, calculate value of n, final pressure and change in entropy.?
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A quantity of gas is compressed according to pv^n= constant the initia...

Given Data:
Initial Pressure (P1) = 1.03 bar
Initial Volume (V1) = 0.98 m^3
Initial Temperature (T1) = 17°C = 290K
Final Temperature (T2) = 115°C = 388K
Amount of Heat Rejected (Q) = 3.78 kJ
Specific Heat at Constant Pressure (cp) = 0.92
Gas Constant (R) = 8.314 J/molK

Finding 'n' Value:
Using the formula pv^n = constant, we can write the equation as:
P1V1^n = P2V2^n
1.03 * 0.98^n = P2 * 0.98^n
1.03 = P2
Therefore, final pressure (P2) = 1.03 bar

Finding Change in Entropy:
From the first law of thermodynamics, we know:
Q = ΔU + W
ΔU = Q - W
ΔU = Q - cp * m * ΔT
m * cp * ΔT = Q
m = Q / (cp * ΔT)
m = 3.78 kJ / (0.92 * 388K - 290K)
m = 0.62 kg

Using the ideal gas equation: P1V1/T1 = P2V2/T2
0.98 * 1.03 / 290 = 1.03 * 0.98 / 388 * V2
V2 = 0.979 m^3

m = 0.62 kg
R = 8.314 J/molK
n = cp / (cp - R)
n = 0.92 / (0.92 - 8.314)
n = 0.92 / -7.394
n = -0.124

Summary:
- The value of 'n' is approximately -0.124.
- The final pressure is 1.03 bar.
- The change in entropy can be calculated using the given amount of heat rejected and specific heat at constant pressure.
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A quantity of gas is compressed according to pv^n= constant the initial pressure and volume being 1.03bar and .98m^3 respectively. The temperature at the start of compression is 17 degree Celsius and at the end it is 115 degree Celsius. The amount of heat rejected during compression is 3.78KJ and cp=.92, calculate value of n, final pressure and change in entropy.?
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A quantity of gas is compressed according to pv^n= constant the initial pressure and volume being 1.03bar and .98m^3 respectively. The temperature at the start of compression is 17 degree Celsius and at the end it is 115 degree Celsius. The amount of heat rejected during compression is 3.78KJ and cp=.92, calculate value of n, final pressure and change in entropy.? for Mechanical Engineering 2024 is part of Mechanical Engineering preparation. The Question and answers have been prepared according to the Mechanical Engineering exam syllabus. Information about A quantity of gas is compressed according to pv^n= constant the initial pressure and volume being 1.03bar and .98m^3 respectively. The temperature at the start of compression is 17 degree Celsius and at the end it is 115 degree Celsius. The amount of heat rejected during compression is 3.78KJ and cp=.92, calculate value of n, final pressure and change in entropy.? covers all topics & solutions for Mechanical Engineering 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A quantity of gas is compressed according to pv^n= constant the initial pressure and volume being 1.03bar and .98m^3 respectively. The temperature at the start of compression is 17 degree Celsius and at the end it is 115 degree Celsius. The amount of heat rejected during compression is 3.78KJ and cp=.92, calculate value of n, final pressure and change in entropy.?.
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