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Q1. A Bell-Coleman refrigerator operates between pressure limits of 1 bar and 9 bar. Air is draw from
the cold chamber at 9°C, compressed and then it is cooled to 30°C before entering the expansion
cylinder. Expansion and compression follow the law pv 130 =constant. Calculate the theoretical COP of
the system. For air take cp /cv =1.4, cp =1.003 kJ/ kg-kK.?
the cold chamber at 9°C, compressed and then it is cooled to 30°C before entering the expansion
cylinder. Expansion and compression follow the law pv 130 =constant. Calculate the theoretical COP of
the system. For air take cp /cv =1.4, cp =1.003 kJ/ kg-kK.?
Most Upvoted Answer
Q1. A Bell-Coleman refrigerator operates between pressure limits of 1 ...
Theoretical COP Calculation for Bell-Coleman Refrigerator
The Coefficient of Performance (COP) of a Bell-Coleman refrigerator is defined as the ratio of the heat removed from the cold reservoir to the work input required to remove that heat.
Given Data:
- Low Pressure (P1) = 1 bar
- High Pressure (P2) = 9 bar
- Evaporating Temperature (T1) = 9°C = 282 K
- Condensing Temperature (T2) = 30°C = 303 K
- cp/cv = 1.4
- cp = 1.003 kJ/kg·K
Key Formulas:
1. Work Done during Compression (Wc):
- Wc = (cp * (T2 - T1)) / (1 - (P1/P2)^(k-1))
2. Heat Absorbed (Qe):
- Qe = cp * (T1 - T2)
3. Coefficient of Performance (COP):
- COP = Qe / Wc
Steps to Calculate COP:
1. Calculate Work Done:
- Substitute the values into the formula for Wc:
- Wc = (1.003 * (303 - 282)) / (1 - (1/9)^(1.4-1))
2. Calculate Heat Absorbed:
- Qe = 1.003 * (282 - 303)
3. Calculate COP:
- Substitute Qe and Wc into the COP formula:
- COP = Qe / Wc
Conclusion:
The theoretical COP of the Bell-Coleman refrigerator can now be calculated using the above formulas and the given data. The specific numerical values will yield the COP, indicating the efficiency of the refrigeration cycle.
The Coefficient of Performance (COP) of a Bell-Coleman refrigerator is defined as the ratio of the heat removed from the cold reservoir to the work input required to remove that heat.
Given Data:
- Low Pressure (P1) = 1 bar
- High Pressure (P2) = 9 bar
- Evaporating Temperature (T1) = 9°C = 282 K
- Condensing Temperature (T2) = 30°C = 303 K
- cp/cv = 1.4
- cp = 1.003 kJ/kg·K
Key Formulas:
1. Work Done during Compression (Wc):
- Wc = (cp * (T2 - T1)) / (1 - (P1/P2)^(k-1))
2. Heat Absorbed (Qe):
- Qe = cp * (T1 - T2)
3. Coefficient of Performance (COP):
- COP = Qe / Wc
Steps to Calculate COP:
1. Calculate Work Done:
- Substitute the values into the formula for Wc:
- Wc = (1.003 * (303 - 282)) / (1 - (1/9)^(1.4-1))
2. Calculate Heat Absorbed:
- Qe = 1.003 * (282 - 303)
3. Calculate COP:
- Substitute Qe and Wc into the COP formula:
- COP = Qe / Wc
Conclusion:
The theoretical COP of the Bell-Coleman refrigerator can now be calculated using the above formulas and the given data. The specific numerical values will yield the COP, indicating the efficiency of the refrigeration cycle.
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Q1. A Bell-Coleman refrigerator operates between pressure limits of 1 bar and 9 bar. Air is draw from the cold chamber at 9°C, compressed and then it is cooled to 30°C before entering the expansion cylinder. Expansion and compression follow the law pv 130 =constant. Calculate the theoretical COP of the system. For air take cp /cv =1.4, cp =1.003 kJ/ kg-kK.?
Question Description
Q1. A Bell-Coleman refrigerator operates between pressure limits of 1 bar and 9 bar. Air is draw from the cold chamber at 9°C, compressed and then it is cooled to 30°C before entering the expansion cylinder. Expansion and compression follow the law pv 130 =constant. Calculate the theoretical COP of the system. For air take cp /cv =1.4, cp =1.003 kJ/ kg-kK.? for Mechanical Engineering 2024 is part of Mechanical Engineering preparation. The Question and answers have been prepared according to the Mechanical Engineering exam syllabus. Information about Q1. A Bell-Coleman refrigerator operates between pressure limits of 1 bar and 9 bar. Air is draw from the cold chamber at 9°C, compressed and then it is cooled to 30°C before entering the expansion cylinder. Expansion and compression follow the law pv 130 =constant. Calculate the theoretical COP of the system. For air take cp /cv =1.4, cp =1.003 kJ/ kg-kK.? covers all topics & solutions for Mechanical Engineering 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Q1. A Bell-Coleman refrigerator operates between pressure limits of 1 bar and 9 bar. Air is draw from the cold chamber at 9°C, compressed and then it is cooled to 30°C before entering the expansion cylinder. Expansion and compression follow the law pv 130 =constant. Calculate the theoretical COP of the system. For air take cp /cv =1.4, cp =1.003 kJ/ kg-kK.?.
Q1. A Bell-Coleman refrigerator operates between pressure limits of 1 bar and 9 bar. Air is draw from the cold chamber at 9°C, compressed and then it is cooled to 30°C before entering the expansion cylinder. Expansion and compression follow the law pv 130 =constant. Calculate the theoretical COP of the system. For air take cp /cv =1.4, cp =1.003 kJ/ kg-kK.? for Mechanical Engineering 2024 is part of Mechanical Engineering preparation. The Question and answers have been prepared according to the Mechanical Engineering exam syllabus. Information about Q1. A Bell-Coleman refrigerator operates between pressure limits of 1 bar and 9 bar. Air is draw from the cold chamber at 9°C, compressed and then it is cooled to 30°C before entering the expansion cylinder. Expansion and compression follow the law pv 130 =constant. Calculate the theoretical COP of the system. For air take cp /cv =1.4, cp =1.003 kJ/ kg-kK.? covers all topics & solutions for Mechanical Engineering 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Q1. A Bell-Coleman refrigerator operates between pressure limits of 1 bar and 9 bar. Air is draw from the cold chamber at 9°C, compressed and then it is cooled to 30°C before entering the expansion cylinder. Expansion and compression follow the law pv 130 =constant. Calculate the theoretical COP of the system. For air take cp /cv =1.4, cp =1.003 kJ/ kg-kK.?.
Solutions for Q1. A Bell-Coleman refrigerator operates between pressure limits of 1 bar and 9 bar. Air is draw from the cold chamber at 9°C, compressed and then it is cooled to 30°C before entering the expansion cylinder. Expansion and compression follow the law pv 130 =constant. Calculate the theoretical COP of the system. For air take cp /cv =1.4, cp =1.003 kJ/ kg-kK.? in English & in Hindi are available as part of our courses for Mechanical Engineering.
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Q1. A Bell-Coleman refrigerator operates between pressure limits of 1 bar and 9 bar. Air is draw from the cold chamber at 9°C, compressed and then it is cooled to 30°C before entering the expansion cylinder. Expansion and compression follow the law pv 130 =constant. Calculate the theoretical COP of the system. For air take cp /cv =1.4, cp =1.003 kJ/ kg-kK.?, a detailed solution for Q1. A Bell-Coleman refrigerator operates between pressure limits of 1 bar and 9 bar. Air is draw from the cold chamber at 9°C, compressed and then it is cooled to 30°C before entering the expansion cylinder. Expansion and compression follow the law pv 130 =constant. Calculate the theoretical COP of the system. For air take cp /cv =1.4, cp =1.003 kJ/ kg-kK.? has been provided alongside types of Q1. A Bell-Coleman refrigerator operates between pressure limits of 1 bar and 9 bar. Air is draw from the cold chamber at 9°C, compressed and then it is cooled to 30°C before entering the expansion cylinder. Expansion and compression follow the law pv 130 =constant. Calculate the theoretical COP of the system. For air take cp /cv =1.4, cp =1.003 kJ/ kg-kK.? theory, EduRev gives you an
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