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Electrons ejected from the surface of a metal, when light of cartain frequency is incident on it, are stopped fully by a retarding potential of 3 volts. Photo electric effect in this metallic surface begins at a frequency 6 x 1014 s-1 . The frequency of the incident light in s-1 is [ Planck′s constant = 6.4 x 10-34 J − sec ; charge on the electron = 1.6 x 10-19C ]
- a)7. 5 x 1013
- b)13.5 x 1013
- c)13.5 x 1014
- d)7.5x1015
Correct answer is option 'C'. Can you explain this answer?
Verified Answer
Electrons ejected from the surface of a metal, when light of cartain f...
According to Einstein's Photo electric equation
hv = hv0 + K.E = hv0 + ev0
⇒ v0 = v0 + ev0 /h
⇒' v0 = 13.5 x1014 Js-1
hv = hv0 + K.E = hv0 + ev0
⇒ v0 = v0 + ev0 /h
⇒' v0 = 13.5 x1014 Js-1
Most Upvoted Answer
Electrons ejected from the surface of a metal, when light of cartain f...
The equation that relates the frequency of the incident light (ν), the work function (φ), and the stopping potential (V) in the photoelectric effect is given by:
eV = hν - φ
Where e is the elementary charge (1.6 x 10^-19 C), h is Planck's constant (6.626 x 10^-34 J·s), and φ is the work function of the metal surface.
In this case, the stopping potential (V) is given as 3 volts. The work function (φ) is not given, but we know that the photoelectric effect begins at a frequency of 6 x 10^14 s^-1.
To find the frequency of the incident light (ν), we can rearrange the equation as follows:
ν = (eV + φ) / h
Since the stopping potential (V) is given as 3 volts, we can substitute the values into the equation:
ν = (1.6 x 10^-19 C * 3 V + φ) / (6.626 x 10^-34 J·s)
Simplifying the equation:
ν = (4.8 x 10^-19 C + φ) / (6.626 x 10^-34 J·s)
Since the work function (φ) is not given, we cannot calculate the exact frequency.
eV = hν - φ
Where e is the elementary charge (1.6 x 10^-19 C), h is Planck's constant (6.626 x 10^-34 J·s), and φ is the work function of the metal surface.
In this case, the stopping potential (V) is given as 3 volts. The work function (φ) is not given, but we know that the photoelectric effect begins at a frequency of 6 x 10^14 s^-1.
To find the frequency of the incident light (ν), we can rearrange the equation as follows:
ν = (eV + φ) / h
Since the stopping potential (V) is given as 3 volts, we can substitute the values into the equation:
ν = (1.6 x 10^-19 C * 3 V + φ) / (6.626 x 10^-34 J·s)
Simplifying the equation:
ν = (4.8 x 10^-19 C + φ) / (6.626 x 10^-34 J·s)
Since the work function (φ) is not given, we cannot calculate the exact frequency.
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Electrons ejected from the surface of a metal, when light of cartain frequency is incident on it, are stopped fully by a retarding potential of 3 volts. Photo electric effect in this metallic surface begins at a frequency 6 x 1014 s-1. The frequency of the incident light in s-1 is [ Planck′s constant = 6.4 x10-34J − sec ; charge on the electron = 1.6 x10-19C ]a)7.5 x1013b)13.5 x1013c)13.5 x1014d)7.5x1015Correct answer is option 'C'. Can you explain this answer?
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Electrons ejected from the surface of a metal, when light of cartain frequency is incident on it, are stopped fully by a retarding potential of 3 volts. Photo electric effect in this metallic surface begins at a frequency 6 x 1014 s-1. The frequency of the incident light in s-1 is [ Planck′s constant = 6.4 x10-34J − sec ; charge on the electron = 1.6 x10-19C ]a)7.5 x1013b)13.5 x1013c)13.5 x1014d)7.5x1015Correct answer is option 'C'. Can you explain this answer? for JEE 2025 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about Electrons ejected from the surface of a metal, when light of cartain frequency is incident on it, are stopped fully by a retarding potential of 3 volts. Photo electric effect in this metallic surface begins at a frequency 6 x 1014 s-1. The frequency of the incident light in s-1 is [ Planck′s constant = 6.4 x10-34J − sec ; charge on the electron = 1.6 x10-19C ]a)7.5 x1013b)13.5 x1013c)13.5 x1014d)7.5x1015Correct answer is option 'C'. Can you explain this answer? covers all topics & solutions for JEE 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Electrons ejected from the surface of a metal, when light of cartain frequency is incident on it, are stopped fully by a retarding potential of 3 volts. Photo electric effect in this metallic surface begins at a frequency 6 x 1014 s-1. The frequency of the incident light in s-1 is [ Planck′s constant = 6.4 x10-34J − sec ; charge on the electron = 1.6 x10-19C ]a)7.5 x1013b)13.5 x1013c)13.5 x1014d)7.5x1015Correct answer is option 'C'. Can you explain this answer?.
Electrons ejected from the surface of a metal, when light of cartain frequency is incident on it, are stopped fully by a retarding potential of 3 volts. Photo electric effect in this metallic surface begins at a frequency 6 x 1014 s-1. The frequency of the incident light in s-1 is [ Planck′s constant = 6.4 x10-34J − sec ; charge on the electron = 1.6 x10-19C ]a)7.5 x1013b)13.5 x1013c)13.5 x1014d)7.5x1015Correct answer is option 'C'. Can you explain this answer? for JEE 2025 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about Electrons ejected from the surface of a metal, when light of cartain frequency is incident on it, are stopped fully by a retarding potential of 3 volts. Photo electric effect in this metallic surface begins at a frequency 6 x 1014 s-1. The frequency of the incident light in s-1 is [ Planck′s constant = 6.4 x10-34J − sec ; charge on the electron = 1.6 x10-19C ]a)7.5 x1013b)13.5 x1013c)13.5 x1014d)7.5x1015Correct answer is option 'C'. Can you explain this answer? covers all topics & solutions for JEE 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Electrons ejected from the surface of a metal, when light of cartain frequency is incident on it, are stopped fully by a retarding potential of 3 volts. Photo electric effect in this metallic surface begins at a frequency 6 x 1014 s-1. The frequency of the incident light in s-1 is [ Planck′s constant = 6.4 x10-34J − sec ; charge on the electron = 1.6 x10-19C ]a)7.5 x1013b)13.5 x1013c)13.5 x1014d)7.5x1015Correct answer is option 'C'. Can you explain this answer?.
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Electrons ejected from the surface of a metal, when light of cartain frequency is incident on it, are stopped fully by a retarding potential of 3 volts. Photo electric effect in this metallic surface begins at a frequency 6 x 1014 s-1. The frequency of the incident light in s-1 is [ Planck′s constant = 6.4 x10-34J − sec ; charge on the electron = 1.6 x10-19C ]a)7.5 x1013b)13.5 x1013c)13.5 x1014d)7.5x1015Correct answer is option 'C'. Can you explain this answer?, a detailed solution for Electrons ejected from the surface of a metal, when light of cartain frequency is incident on it, are stopped fully by a retarding potential of 3 volts. Photo electric effect in this metallic surface begins at a frequency 6 x 1014 s-1. The frequency of the incident light in s-1 is [ Planck′s constant = 6.4 x10-34J − sec ; charge on the electron = 1.6 x10-19C ]a)7.5 x1013b)13.5 x1013c)13.5 x1014d)7.5x1015Correct answer is option 'C'. Can you explain this answer? has been provided alongside types of Electrons ejected from the surface of a metal, when light of cartain frequency is incident on it, are stopped fully by a retarding potential of 3 volts. Photo electric effect in this metallic surface begins at a frequency 6 x 1014 s-1. The frequency of the incident light in s-1 is [ Planck′s constant = 6.4 x10-34J − sec ; charge on the electron = 1.6 x10-19C ]a)7.5 x1013b)13.5 x1013c)13.5 x1014d)7.5x1015Correct answer is option 'C'. Can you explain this answer? theory, EduRev gives you an
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