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The fpt depression an constant for water -18.6 degree Celsius/ mole .if na2so4 is dissolved in 45 g h2o the freezing point is changef by -3.82 degree Celsius . Calculated the van't haff factor(i) for na2so4?
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The fpt depression an constant for water -18.6 degree Celsius/ mole .if na2so4 is dissolved in 45 g h2o the freezing point is changef by -3.82 degree Celsius . Calculated the van't haff factor(i) for na2so4?
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The fpt depression an constant for water -18.6 degree Celsius/ mole .if na2so4 is dissolved in 45 g h2o the freezing point is changef by -3.82 degree Celsius . Calculated the van't haff factor(i) for na2so4? for Class 12 2024 is part of Class 12 preparation. The Question and answers have been prepared according to the Class 12 exam syllabus. Information about The fpt depression an constant for water -18.6 degree Celsius/ mole .if na2so4 is dissolved in 45 g h2o the freezing point is changef by -3.82 degree Celsius . Calculated the van't haff factor(i) for na2so4? covers all topics & solutions for Class 12 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The fpt depression an constant for water -18.6 degree Celsius/ mole .if na2so4 is dissolved in 45 g h2o the freezing point is changef by -3.82 degree Celsius . Calculated the van't haff factor(i) for na2so4?.
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