Methylphenylether can be obtained by reactinga)Phenolate ions with met...
By the Williamson synthesis
C6H5O - + CH3l → C6H5OCH3 + l -
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Methylphenylether can be obtained by reactinga)Phenolate ions with met...
Reaction to obtain Methylphenylether
The correct option to obtain Methylphenylether is 'A', which involves the reaction of phenolate ions with methyl iodide. Let us understand this reaction in detail:
Phenolate ions and Methyl Iodide
Phenolate ions are the conjugate base of phenol, which is formed by removing a proton from the hydroxyl group (-OH) of phenol. Phenol is an aromatic compound with a benzene ring attached to a hydroxyl group (-OH).
Methyl iodide is a methylating agent, which means it can add a methyl group (-CH3) to a molecule. It is a halogenalkane, which means it contains a halogen atom (iodine in this case) attached to a carbon atom.
The reaction between phenolate ions and methyl iodide is an example of Williamson ether synthesis. In this reaction, the phenolate ion acts as a nucleophile and attacks the methyl iodide, which acts as an electrophile.
The mechanism of the reaction involves the following steps:
- The lone pair of electrons on the oxygen atom of the phenolate ion attacks the carbon atom of the methyl iodide, forming a covalent bond.
- The iodide ion leaves as a leaving group, forming a methylphenol intermediate.
- The intermediate loses a proton from the hydroxyl group, forming the final product, Methylphenylether.
The overall reaction can be represented as follows:
Phenolate ion + Methyl iodide → Methylphenol intermediate → Methylphenylether + Iodide ion
Therefore, the correct option to obtain Methylphenylether is 'A', which involves the reaction of phenolate ions with methyl iodide.
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