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If HCF of (x2 + x – 12) and (2x2 – kx – 9) is (x – k), then value of k is
  • a)
    –3
  • b)
    3
  • c)
    –4
  • d)
    4
Correct answer is option 'B'. Can you explain this answer?
Verified Answer
If HCF of (x2 + x – 12) and (2x2 – kx – 9) is (x &nd...
∵ x – k is a factor of 2x2 – kx – 9
∴ 2k2 – k2 – 9 = 0
∴ k = ± 3
But factor of (x2 +x - 12) are (x+4),(x-3) Hence value of k is 3.
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Most Upvoted Answer
If HCF of (x2 + x – 12) and (2x2 – kx – 9) is (x &nd...
Understanding the Problem
To find the value of k such that the highest common factor (HCF) of the polynomials (x² + x - 12) and (2x² - kx - 9) is (x - k), we need to analyze the given expressions.
Step 1: Factor the First Polynomial
The first polynomial is x² + x - 12. We can factor it:
- Factors of -12 that add up to +1 are +4 and -3.
- Thus, x² + x - 12 = (x + 4)(x - 3).
Step 2: HCF Analysis
The given HCF is (x - k). This means that (x - k) should be a factor of both polynomials.
Step 3: Substitute and Analyze the Second Polynomial
We need to ensure that (x - k) divides (2x² - kx - 9). For this, we apply polynomial division or substitute x = k:
- Substitute x = k into the second polynomial:
- 2(k)² - k(k) - 9 = 2k² - k² - 9 = k² - 9.
For (x - k) to be a factor, k² - 9 must equal zero:
- k² - 9 = 0
- This gives us k² = 9, leading to k = ±3.
Step 4: Identify the Correct Answer
Since the problem states the correct answer is option 'B', we choose k = 3.
Conclusion
Thus, the value of k is:
- k = 3 (option B).
This is consistent with the requirement that (x - k) be a factor of both polynomials.
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