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If 20 sin2θ + 21 cos θ – 24 = 0 & 7π/4 < θ < 2π then the values of cot θ/2 is
  • a)
    3
  • b)
     
  • c)
  • d)
     – 3
Correct answer is option 'D'. Can you explain this answer?
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If 20 sin2θ + 21 cos θ –24 = 0 &7π/4< θ < 2π then the values of cotθ/2isa)3b)c)–d)–3Correct answer is option 'D'. Can you explain this answer?
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If 20 sin2θ + 21 cos θ –24 = 0 &7π/4< θ < 2π then the values of cotθ/2isa)3b)c)–d)–3Correct answer is option 'D'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about If 20 sin2θ + 21 cos θ –24 = 0 &7π/4< θ < 2π then the values of cotθ/2isa)3b)c)–d)–3Correct answer is option 'D'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for If 20 sin2θ + 21 cos θ –24 = 0 &7π/4< θ < 2π then the values of cotθ/2isa)3b)c)–d)–3Correct answer is option 'D'. Can you explain this answer?.
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