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The average age of a group of 10 students was 20 years. The average age increased by two years when two new students joined the group. What is the average age of the two new students who joined the group?
- a)22 years
- b)30 years
- c)44 years
- d)32 years
Correct answer is option 'D'. Can you explain this answer?
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Most Upvoted Answer
The average age of a group of 10 students was 20 years. The average ag...
Given:
- The average age of a group of 10 students was 20 years.
- The average age increased by two years when two new students joined the group.
To find:
- The average age of the two new students who joined the group.
Solution:
Let the sum of ages of 10 students be S.
So, average age of 10 students = S/10 = 20
Therefore, S = 200
When two new students join, the total number of students becomes 12.
Let the sum of ages of new students be x.
So, new average = (S + x)/12 = 22
Therefore, S + x = 264
Substituting the value of S from the first equation, we get:
200 + x = 264
x = 64
Therefore, the sum of ages of the two new students is 64.
And, the average age of the two new students who joined the group is given by:
Average age = Sum of ages/Number of students = 64/2 = 32
Hence, the average age of the two new students who joined the group is 32 years.
- The average age of a group of 10 students was 20 years.
- The average age increased by two years when two new students joined the group.
To find:
- The average age of the two new students who joined the group.
Solution:
Let the sum of ages of 10 students be S.
So, average age of 10 students = S/10 = 20
Therefore, S = 200
When two new students join, the total number of students becomes 12.
Let the sum of ages of new students be x.
So, new average = (S + x)/12 = 22
Therefore, S + x = 264
Substituting the value of S from the first equation, we get:
200 + x = 264
x = 64
Therefore, the sum of ages of the two new students is 64.
And, the average age of the two new students who joined the group is given by:
Average age = Sum of ages/Number of students = 64/2 = 32
Hence, the average age of the two new students who joined the group is 32 years.
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Community Answer
The average age of a group of 10 students was 20 years. The average ag...
[{(20+2)×(10+2)} - (20 × 10)] / 2
= [(22 × 12) - (200)] / 2
= [264 - 200] / 2
= 64/2 = 32
= [(22 × 12) - (200)] / 2
= [264 - 200] / 2
= 64/2 = 32
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The average age of a group of 10 students was 20 years. The average age increased by two years when two new students joined the group. What is the average age of the two new students who joined the group?a)22 yearsb)30 yearsc)44 yearsd)32 yearsCorrect answer is option 'D'. Can you explain this answer?
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