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Suppose ω is an imaginary cube root of unity. If (1+ω2)m = (1+ω4)m, then the least positive integral value of m is
  • a)
    6
  • b)
    5
  • c)
    4
  • d)
    3
Correct answer is option 'D'. Can you explain this answer?
Most Upvoted Answer
Suppose ω is an imaginary cube root of unity. If (1+ω2)m =...
The given equation reduces to (−ω)m    = (−ω2)m 
⇒ ωm  = 1 
⇒ m = 3
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Suppose ω is an imaginary cube root of unity. If (1+ω2)m =...
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Suppose ω is an imaginary cube root of unity. If (1+ω2)m = (1+ω4)m, then the least positive integral value of m isa)6b)5c)4d)3Correct answer is option 'D'. Can you explain this answer?
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