Class 12 Exam  >  Class 12 Questions  >  Maximum velocity of the photoelectrons emitte... Start Learning for Free
Maximum velocity of the photoelectrons emitted by a metal surface is 1.2 × 106 m/s. assuming the specific charge of the electron to be 1.8 × 1011 C/kg, the value of the stopping potential in volt will be:
  • a)
    2
  • b)
    3
  • c)
    4
  • d)
    6
Correct answer is option 'C'. Can you explain this answer?
Most Upvoted Answer
Maximum velocity of the photoelectrons emitted by a metal surface is 1...
Free Test
Community Answer
Maximum velocity of the photoelectrons emitted by a metal surface is 1...
In order to determine the maximum velocity of the photoelectrons emitted by a metal surface, we can use the equation for the kinetic energy of an electron:

K.E. = 1/2 * mv^2

where K.E. is the kinetic energy, m is the mass of the electron, and v is the velocity of the electron.

The maximum velocity of the photoelectrons can be found by equating the kinetic energy to the energy of the incident photon:

K.E. = energy of incident photon

The energy of a photon can be calculated using the equation:

E = hf

where E is the energy of the photon, h is Planck's constant, and f is the frequency of the incident light.

So, we have:

1/2 * mv^2 = hf

Rearranging the equation, we get:

v = √(2hf/m)

Given that the maximum velocity of the photoelectrons is 1.2, we can substitute this value into the equation to solve for the frequency:

1.2 = √(2hf/m)

Squaring both sides of the equation, we get:

1.44 = 2hf/m

Now, solving for f, we get:

f = 1.44 * m / (2h)

Note that the mass of an electron is approximately 9.11 x 10^-31 kg and Planck's constant is approximately 6.63 x 10^-34 Js.

Substituting the values into the equation:

f ≈ 1.44 * (9.11 x 10^-31 kg) / (2 * 6.63 x 10^-34 Js)

f ≈ 1.97 x 10^15 Hz

Therefore, the maximum velocity of the photoelectrons emitted by the metal surface is approximately 1.2.
Explore Courses for Class 12 exam

Similar Class 12 Doubts

Maximum velocity of the photoelectrons emitted by a metal surface is 1.2 × 106 m/s. assuming the specific charge of the electron to be 1.8 × 1011 C/kg, the value of the stopping potential in volt will be:a)2b)3c)4d)6Correct answer is option 'C'. Can you explain this answer?
Question Description
Maximum velocity of the photoelectrons emitted by a metal surface is 1.2 × 106 m/s. assuming the specific charge of the electron to be 1.8 × 1011 C/kg, the value of the stopping potential in volt will be:a)2b)3c)4d)6Correct answer is option 'C'. Can you explain this answer? for Class 12 2024 is part of Class 12 preparation. The Question and answers have been prepared according to the Class 12 exam syllabus. Information about Maximum velocity of the photoelectrons emitted by a metal surface is 1.2 × 106 m/s. assuming the specific charge of the electron to be 1.8 × 1011 C/kg, the value of the stopping potential in volt will be:a)2b)3c)4d)6Correct answer is option 'C'. Can you explain this answer? covers all topics & solutions for Class 12 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Maximum velocity of the photoelectrons emitted by a metal surface is 1.2 × 106 m/s. assuming the specific charge of the electron to be 1.8 × 1011 C/kg, the value of the stopping potential in volt will be:a)2b)3c)4d)6Correct answer is option 'C'. Can you explain this answer?.
Solutions for Maximum velocity of the photoelectrons emitted by a metal surface is 1.2 × 106 m/s. assuming the specific charge of the electron to be 1.8 × 1011 C/kg, the value of the stopping potential in volt will be:a)2b)3c)4d)6Correct answer is option 'C'. Can you explain this answer? in English & in Hindi are available as part of our courses for Class 12. Download more important topics, notes, lectures and mock test series for Class 12 Exam by signing up for free.
Here you can find the meaning of Maximum velocity of the photoelectrons emitted by a metal surface is 1.2 × 106 m/s. assuming the specific charge of the electron to be 1.8 × 1011 C/kg, the value of the stopping potential in volt will be:a)2b)3c)4d)6Correct answer is option 'C'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of Maximum velocity of the photoelectrons emitted by a metal surface is 1.2 × 106 m/s. assuming the specific charge of the electron to be 1.8 × 1011 C/kg, the value of the stopping potential in volt will be:a)2b)3c)4d)6Correct answer is option 'C'. Can you explain this answer?, a detailed solution for Maximum velocity of the photoelectrons emitted by a metal surface is 1.2 × 106 m/s. assuming the specific charge of the electron to be 1.8 × 1011 C/kg, the value of the stopping potential in volt will be:a)2b)3c)4d)6Correct answer is option 'C'. Can you explain this answer? has been provided alongside types of Maximum velocity of the photoelectrons emitted by a metal surface is 1.2 × 106 m/s. assuming the specific charge of the electron to be 1.8 × 1011 C/kg, the value of the stopping potential in volt will be:a)2b)3c)4d)6Correct answer is option 'C'. Can you explain this answer? theory, EduRev gives you an ample number of questions to practice Maximum velocity of the photoelectrons emitted by a metal surface is 1.2 × 106 m/s. assuming the specific charge of the electron to be 1.8 × 1011 C/kg, the value of the stopping potential in volt will be:a)2b)3c)4d)6Correct answer is option 'C'. Can you explain this answer? tests, examples and also practice Class 12 tests.
Explore Courses for Class 12 exam
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
10M+ students study on EduRev