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How to create a dynamic array of pointers (to integers) of size 10 using new in C++? Here, one can create a non-dynamic array using int *arr[10]
- a)int *arr = new int *[10];
- b)int **arr = new int *[10];
- c)int *arr = new int [10];
- d)Not Possible
Correct answer is option 'B'. Can you explain this answer?
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How to create a dynamic array of pointers (to integers) of size 10 usi...
Creating a Dynamic Array of Pointers to Integers in C Using new
When working with arrays in C, it is often necessary to create dynamic arrays that can be resized at runtime. In this case, we want to create a dynamic array of pointers to integers of size 10 using new in C.
Option B is the correct answer because it creates a dynamic array of pointers to integers of size 10 using new in C. Here is how it works:
- Option A: int *arr = new int *[10];
This option creates a static array of 10 pointers to integers. It is not dynamic because the size of the array cannot be changed at runtime. Therefore, this option is not correct.
- Option B: int **arr = new int *[10];
This option creates a dynamic array of 10 pointers to integers. The double asterisk indicates that we are creating an array of pointers. The new keyword allocates memory for the array and returns a pointer to the first element. Therefore, this option is correct.
- Option C: int *arr = new int [10];
This option creates a dynamic array of 10 integers. It is not an array of pointers to integers, so it is not correct for our purposes.
- Option D: Not Possible
This option is not correct because it is possible to create dynamic arrays of pointers to integers in C using new.
In summary, option B is the correct answer because it creates a dynamic array of pointers to integers of size 10 using new in C.
When working with arrays in C, it is often necessary to create dynamic arrays that can be resized at runtime. In this case, we want to create a dynamic array of pointers to integers of size 10 using new in C.
Option B is the correct answer because it creates a dynamic array of pointers to integers of size 10 using new in C. Here is how it works:
- Option A: int *arr = new int *[10];
This option creates a static array of 10 pointers to integers. It is not dynamic because the size of the array cannot be changed at runtime. Therefore, this option is not correct.
- Option B: int **arr = new int *[10];
This option creates a dynamic array of 10 pointers to integers. The double asterisk indicates that we are creating an array of pointers. The new keyword allocates memory for the array and returns a pointer to the first element. Therefore, this option is correct.
- Option C: int *arr = new int [10];
This option creates a dynamic array of 10 integers. It is not an array of pointers to integers, so it is not correct for our purposes.
- Option D: Not Possible
This option is not correct because it is possible to create dynamic arrays of pointers to integers in C using new.
In summary, option B is the correct answer because it creates a dynamic array of pointers to integers of size 10 using new in C.
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How to create a dynamic array of pointers (to integers) of size 10 using new in C++? Here, one can create a non-dynamic array using int *arr[10]a)int *arr = new int *[10];b)int **arr = new int *[10];c)int *arr = new int [10];d)Not PossibleCorrect answer is option 'B'. Can you explain this answer? for Back-End Programming 2025 is part of Back-End Programming preparation. The Question and answers have been prepared according to the Back-End Programming exam syllabus. Information about How to create a dynamic array of pointers (to integers) of size 10 using new in C++? Here, one can create a non-dynamic array using int *arr[10]a)int *arr = new int *[10];b)int **arr = new int *[10];c)int *arr = new int [10];d)Not PossibleCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for Back-End Programming 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for How to create a dynamic array of pointers (to integers) of size 10 using new in C++? Here, one can create a non-dynamic array using int *arr[10]a)int *arr = new int *[10];b)int **arr = new int *[10];c)int *arr = new int [10];d)Not PossibleCorrect answer is option 'B'. Can you explain this answer?.
How to create a dynamic array of pointers (to integers) of size 10 using new in C++? Here, one can create a non-dynamic array using int *arr[10]a)int *arr = new int *[10];b)int **arr = new int *[10];c)int *arr = new int [10];d)Not PossibleCorrect answer is option 'B'. Can you explain this answer? for Back-End Programming 2025 is part of Back-End Programming preparation. The Question and answers have been prepared according to the Back-End Programming exam syllabus. Information about How to create a dynamic array of pointers (to integers) of size 10 using new in C++? Here, one can create a non-dynamic array using int *arr[10]a)int *arr = new int *[10];b)int **arr = new int *[10];c)int *arr = new int [10];d)Not PossibleCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for Back-End Programming 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for How to create a dynamic array of pointers (to integers) of size 10 using new in C++? Here, one can create a non-dynamic array using int *arr[10]a)int *arr = new int *[10];b)int **arr = new int *[10];c)int *arr = new int [10];d)Not PossibleCorrect answer is option 'B'. Can you explain this answer?.
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