A father is three times as old as his son. After fifteen years the fat...
Problem Statement:
A father is three times as old as his son. After fifteen years the father will be twice as old as his son's age at that time. Hence the father's present age is?
Solution:
Let the present age of the son be x.
Then the present age of the father will be 3x.
After fifteen years, the age of the son will be x+15 and the age of the father will be 3x+15.
According to the problem statement, after fifteen years the father will be twice as old as his son's age at that time. Hence we can write the following equation:
3x+15 = 2(x+15)
Solving the above equation, we get:
3x+15 = 2x+30
x = 15
Therefore, the present age of the son is 15 years.
The present age of the father can be found by substituting x=15 in the equation 3x, which gives:
Present age of the father = 3x = 3(15) = 45 years.
Hence, the father's present age is 45 years.
Answer:
The father's present age is 45 years.
A father is three times as old as his son. After fifteen years the fat...
Before 15 years
F = 3S
after 15 years
F + 15
S + 15
F = 2S
F + 15 = 2 (S + 15) we know that F= 3S
3S + 15 = 2 (S + 15)
3S - 2S = 30 - 15
S= 15 this is the son age
F = 3S = 3(15)
F = 45
so, the father's present age is 45.