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0.066 gram of metal was deposited when a current of 2 amperes is passed through a metal ion solution for 100 seconds. What is the electrochemical equivalent (in gram coulomb -1) of the metal?
  • a)
    3. 3 x 10−6
  • b)
    3.3 x 10−4
  • c)
    0.033
  • d)
    3.3
Correct answer is option 'B'. Can you explain this answer?
Verified Answer
0.066 gram of metal was deposited when a current of 2 amperes is passe...

= 3.3 x 10-4 gm coulomb
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0.066 gram of metal was deposited when a current of 2 amperes is passe...
-4
b) 3.3 x 10-5
c) 6.6 x 10-4
d) 6.6 x 10-5

First, we need to calculate the total charge that passed through the solution using the formula Q = It, where Q is the charge (in coulombs), I is the current (in amperes), and t is the time (in seconds).

Q = 2 A x 100 s = 200 C

Next, we can use the formula for electrochemical equivalent:

EE = m/Q

where EE is the electrochemical equivalent (in gC-1), m is the mass of the metal deposited (in grams), and Q is the total charge passed (in coulombs).

EE = 0.066 g / 200 C = 3.3 x 10-4 gC-1

Therefore, the answer is (a) 3.3 x 10-4.
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0.066 gram of metal was deposited when a current of 2 amperes is passe...
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0.066 gram of metal was deposited when a current of 2 amperes is passed through a metal ion solution for 100 seconds. What is the electrochemical equivalent (in gram coulomb -1) of the metal?a)3. 3 x 10−6b)3.3 x 10−4c)0.033d)3.3Correct answer is option 'B'. Can you explain this answer?
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