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The heat of combustion of methane at 298K is expressed byC H 4 g + 2 O 2 g → C O 2 g + 2 H 2 O l , Δ H = − 890.2 k J . The magnitude of Δ E of the reaction at this temperature isa)Infinityb)Less than Δ Hc)Equal to Δ Hd)Greater than Δ HCorrect answer is option 'B'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about The heat of combustion of methane at 298K is expressed byC H 4 g + 2 O 2 g → C O 2 g + 2 H 2 O l , Δ H = − 890.2 k J . The magnitude of Δ E of the reaction at this temperature isa)Infinityb)Less than Δ Hc)Equal to Δ Hd)Greater than Δ HCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The heat of combustion of methane at 298K is expressed byC H 4 g + 2 O 2 g → C O 2 g + 2 H 2 O l , Δ H = − 890.2 k J . The magnitude of Δ E of the reaction at this temperature isa)Infinityb)Less than Δ Hc)Equal to Δ Hd)Greater than Δ HCorrect answer is option 'B'. Can you explain this answer?.

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