Two resistances 100 _ 3 ohm and 200 _ 4 ohm are connected in serie...
Calculation of Equivalent Resistance
When two resistors are connected in series, their equivalent resistance is the sum of their individual resistances.
Therefore, the equivalent resistance (R) is given by:
R = R1 + R2
where R1 is the resistance of the first resistor and R2 is the resistance of the second resistor.
Substituting the given values, we get:
R = 100 _ 3 + 200 _ 4
R = 300 + 800
R = 1100 ohm
Therefore, the equivalent resistance of the two resistors is 1100 ohm.
Calculation of Error Limits
To calculate the error limits, we need to use the formula:
δR = R x [(δR1/R1) + (δR2/R2)]
where δR is the error in the equivalent resistance, δR1 and δR2 are the errors in the individual resistances, and R1 and R2 are the individual resistances.
Substituting the given values, we get:
δR = 1100 x [(3/100) + (4/200)]
δR = 1100 x [0.03 + 0.02]
δR = 1100 x 0.05
δR = 55 ohm
Therefore, the error limits for the equivalent resistance are ±55 ohm.
Explanation
In this problem, we were given two resistors connected in series, and we were asked to find the equivalent resistance with error limits. We used the formula for calculating the equivalent resistance of two resistors in series, which is the sum of their individual resistances. We then used the formula for calculating the error limits in the equivalent resistance, which takes into account the errors in the individual resistances. The final answer was the equivalent resistance with error limits of ±55 ohm.
Two resistances 100 _ 3 ohm and 200 _ 4 ohm are connected in serie...
R=r1+r2
=
300+/- 7Ω
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