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Which one of the following high-spin complexes has the largest CFSE (Crystal field stabilization energy)?Options
- a)[Mn(H2O6)]2+
- b)[Cr(H2O)6]2+
- c)[Mn(H2O)6]3+
- d)[Cr(H2O)6]3+
Correct answer is option 'D'. Can you explain this answer?
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Which one of the following high-spin complexes has the largest CFSE (C...
Cation with higher oxidation state has a larger value of CFSE and CFSE decrease with the increase of the number of d-electrons.
Most Upvoted Answer
Which one of the following high-spin complexes has the largest CFSE (C...
Answer:
To determine which complex has the largest Crystal Field Stabilization Energy (CFSE), we need to consider the number of unpaired electrons in each complex. CFSE is directly proportional to the number of unpaired electrons.
Let's analyze each complex:
[Mn(H2O)6]2:
- The oxidation state of Mn is +2.
- The electronic configuration of Mn2+ is 3d5.
- The d-orbitals of Mn2+ will be split by the crystal field created by the surrounding water ligands.
- In an octahedral crystal field, the t2g set (dxy, dyz, dzx) will be lower in energy, while the eg set (dx2-y2, dz2) will be higher in energy.
- There are 5 unpaired electrons in the t2g set, resulting in a high-spin complex.
[Cr(H2O)6]2:
- The oxidation state of Cr is +2.
- The electronic configuration of Cr2+ is 3d4.
- The d-orbitals of Cr2+ will be split by the crystal field created by the surrounding water ligands.
- In an octahedral crystal field, the t2g set (dxy, dyz, dzx) will be lower in energy, while the eg set (dx2-y2, dz2) will be higher in energy.
- There are 4 unpaired electrons in the t2g set, resulting in a high-spin complex.
[Mn(H2O)6]3:
- The oxidation state of Mn is +3.
- The electronic configuration of Mn3+ is 3d4.
- The d-orbitals of Mn3+ will be split by the crystal field created by the surrounding water ligands.
- In an octahedral crystal field, the t2g set (dxy, dyz, dzx) will be lower in energy, while the eg set (dx2-y2, dz2) will be higher in energy.
- There are 4 unpaired electrons in the t2g set, resulting in a high-spin complex.
[Cr(H2O)6]3:
- The oxidation state of Cr is +3.
- The electronic configuration of Cr3+ is 3d3.
- The d-orbitals of Cr3+ will be split by the crystal field created by the surrounding water ligands.
- In an octahedral crystal field, the t2g set (dxy, dyz, dzx) will be lower in energy, while the eg set (dx2-y2, dz2) will be higher in energy.
- There are 3 unpaired electrons in the t2g set, resulting in a high-spin complex.
Conclusion:
From the analysis, we can see that the complex [Cr(H2O)6]3 has the smallest number of unpaired electrons (3), resulting in the largest CFSE. Therefore, the correct answer is option 'D' [Cr(H2O)6]3.
To determine which complex has the largest Crystal Field Stabilization Energy (CFSE), we need to consider the number of unpaired electrons in each complex. CFSE is directly proportional to the number of unpaired electrons.
Let's analyze each complex:
[Mn(H2O)6]2:
- The oxidation state of Mn is +2.
- The electronic configuration of Mn2+ is 3d5.
- The d-orbitals of Mn2+ will be split by the crystal field created by the surrounding water ligands.
- In an octahedral crystal field, the t2g set (dxy, dyz, dzx) will be lower in energy, while the eg set (dx2-y2, dz2) will be higher in energy.
- There are 5 unpaired electrons in the t2g set, resulting in a high-spin complex.
[Cr(H2O)6]2:
- The oxidation state of Cr is +2.
- The electronic configuration of Cr2+ is 3d4.
- The d-orbitals of Cr2+ will be split by the crystal field created by the surrounding water ligands.
- In an octahedral crystal field, the t2g set (dxy, dyz, dzx) will be lower in energy, while the eg set (dx2-y2, dz2) will be higher in energy.
- There are 4 unpaired electrons in the t2g set, resulting in a high-spin complex.
[Mn(H2O)6]3:
- The oxidation state of Mn is +3.
- The electronic configuration of Mn3+ is 3d4.
- The d-orbitals of Mn3+ will be split by the crystal field created by the surrounding water ligands.
- In an octahedral crystal field, the t2g set (dxy, dyz, dzx) will be lower in energy, while the eg set (dx2-y2, dz2) will be higher in energy.
- There are 4 unpaired electrons in the t2g set, resulting in a high-spin complex.
[Cr(H2O)6]3:
- The oxidation state of Cr is +3.
- The electronic configuration of Cr3+ is 3d3.
- The d-orbitals of Cr3+ will be split by the crystal field created by the surrounding water ligands.
- In an octahedral crystal field, the t2g set (dxy, dyz, dzx) will be lower in energy, while the eg set (dx2-y2, dz2) will be higher in energy.
- There are 3 unpaired electrons in the t2g set, resulting in a high-spin complex.
Conclusion:
From the analysis, we can see that the complex [Cr(H2O)6]3 has the smallest number of unpaired electrons (3), resulting in the largest CFSE. Therefore, the correct answer is option 'D' [Cr(H2O)6]3.
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Which one of the following high-spin complexes has the largest CFSE (Crystal field stabilization energy)?Optionsa)[Mn(H2O6)]2+b)[Cr(H2O)6]2+c)[Mn(H2O)6]3+d)[Cr(H2O)6]3+Correct answer is option 'D'. Can you explain this answer?
Question Description
Which one of the following high-spin complexes has the largest CFSE (Crystal field stabilization energy)?Optionsa)[Mn(H2O6)]2+b)[Cr(H2O)6]2+c)[Mn(H2O)6]3+d)[Cr(H2O)6]3+Correct answer is option 'D'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about Which one of the following high-spin complexes has the largest CFSE (Crystal field stabilization energy)?Optionsa)[Mn(H2O6)]2+b)[Cr(H2O)6]2+c)[Mn(H2O)6]3+d)[Cr(H2O)6]3+Correct answer is option 'D'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Which one of the following high-spin complexes has the largest CFSE (Crystal field stabilization energy)?Optionsa)[Mn(H2O6)]2+b)[Cr(H2O)6]2+c)[Mn(H2O)6]3+d)[Cr(H2O)6]3+Correct answer is option 'D'. Can you explain this answer?.
Which one of the following high-spin complexes has the largest CFSE (Crystal field stabilization energy)?Optionsa)[Mn(H2O6)]2+b)[Cr(H2O)6]2+c)[Mn(H2O)6]3+d)[Cr(H2O)6]3+Correct answer is option 'D'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about Which one of the following high-spin complexes has the largest CFSE (Crystal field stabilization energy)?Optionsa)[Mn(H2O6)]2+b)[Cr(H2O)6]2+c)[Mn(H2O)6]3+d)[Cr(H2O)6]3+Correct answer is option 'D'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Which one of the following high-spin complexes has the largest CFSE (Crystal field stabilization energy)?Optionsa)[Mn(H2O6)]2+b)[Cr(H2O)6]2+c)[Mn(H2O)6]3+d)[Cr(H2O)6]3+Correct answer is option 'D'. Can you explain this answer?.
Solutions for Which one of the following high-spin complexes has the largest CFSE (Crystal field stabilization energy)?Optionsa)[Mn(H2O6)]2+b)[Cr(H2O)6]2+c)[Mn(H2O)6]3+d)[Cr(H2O)6]3+Correct answer is option 'D'. Can you explain this answer? in English & in Hindi are available as part of our courses for JEE.
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