If u and v are unit vectors and θis the acuteangle between them,...
If u and v are unit vectors, it means that their magnitudes are equal to 1. Thus, ||u|| = ||v|| = 1.
Given that ||u + v|| = 2, we want to prove that ||u - v|| = 2.
Using the triangle inequality, we have:
||u + v|| ≤ ||u|| + ||v||
Since ||u|| = ||v|| = 1, the inequality becomes:
||u + v|| ≤ 1 + 1
||u + v|| ≤ 2
Since we are given that ||u + v|| = 2, the inequality becomes:
2 ≤ 2
This inequality is true, so the triangle inequality holds.
Now, let's consider ||u - v||:
||u - v|| = ||u + (-v)||
Since -v is the additive inverse of v, its magnitude is the same as v's magnitude, so ||-v|| = ||v|| = 1.
Using the triangle inequality again, we have:
||u + (-v)|| ≤ ||u|| + ||-v||
Since ||u|| = 1 and ||-v|| = 1, the inequality becomes:
||u + (-v)|| ≤ 1 + 1
||u + (-v)|| ≤ 2
However, since we are given that ||u + v|| = 2, we can replace u + (-v) with u + v in the inequality:
||u + v|| ≤ 2
Therefore, ||u - v|| ≤ 2.
But we also know that ||u - v|| ≥ 0, since magnitudes are always non-negative.
Since ||u - v|| ≤ 2 and ||u - v|| ≥ 0, the only possible value for ||u - v|| is 2.
Therefore, ||u - v|| = 2.
In conclusion, if u and v are unit vectors and ||u + v|| = 2, then ||u - v|| = 2.
If u and v are unit vectors and θis the acuteangle between them,...