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Photons with energy 5eV are incident on a cathode C, on a photoelectric cell. The maximum energy of the emitted photoelectrons is 2eV. When photons of energy 6eV are incident on C, no photoelectrons will reach the anode A if the stopping potential of A relative to C is
- a)3V
- b)_3V
- c)_1V
- d)4V
Correct answer is option 'B'. Can you explain this answer?
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Verified Answer
Photons with energy 5eV are incident on a cathode C, on a photoelectri...
When 5eV is incident the kinetic energy is 2eV it simply means the work function is W=5eV−2eV=3eV
Similarly, when 6eV is incident the kinetic energy should be 6eV−W=6eV−3eV=3eV
it simply means to stop them we need a negative potential at anode equal to 3eV/e=3V
So, the answer is −3V i.e. option B is correct.
Similarly, when 6eV is incident the kinetic energy should be 6eV−W=6eV−3eV=3eV
it simply means to stop them we need a negative potential at anode equal to 3eV/e=3V
So, the answer is −3V i.e. option B is correct.
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Photons with energy 5eV are incident on a cathode C, on a photoelectri...
Explanation:
Photoelectric Effect:
- In the photoelectric effect, photons incident on a metal surface can eject electrons from the surface, creating photoelectrons.
Energy Considerations:
- When photons with energy 5eV are incident on the cathode C, the maximum energy of the emitted photoelectrons is 2eV.
- This implies that the work function of the metal is 3eV (5eV - 2eV).
Stopping Potential:
- The stopping potential is the potential difference between the cathode C and the anode A that prevents photoelectrons from reaching the anode.
- For no photoelectrons to reach the anode when photons of energy 6eV are incident, the stopping potential must equal the energy of the incident photons minus the work function.
Calculation:
- For photons with energy 6eV, the work function is 3eV.
- So, the stopping potential relative to C is 6eV - 3eV = 3V.
- Since the question asks for the potential relative to C, the actual stopping potential is -3V (negative because it opposes the motion of the electrons).
Therefore, the correct answer is option 'B' which is -3V.
Photoelectric Effect:
- In the photoelectric effect, photons incident on a metal surface can eject electrons from the surface, creating photoelectrons.
Energy Considerations:
- When photons with energy 5eV are incident on the cathode C, the maximum energy of the emitted photoelectrons is 2eV.
- This implies that the work function of the metal is 3eV (5eV - 2eV).
Stopping Potential:
- The stopping potential is the potential difference between the cathode C and the anode A that prevents photoelectrons from reaching the anode.
- For no photoelectrons to reach the anode when photons of energy 6eV are incident, the stopping potential must equal the energy of the incident photons minus the work function.
Calculation:
- For photons with energy 6eV, the work function is 3eV.
- So, the stopping potential relative to C is 6eV - 3eV = 3V.
- Since the question asks for the potential relative to C, the actual stopping potential is -3V (negative because it opposes the motion of the electrons).
Therefore, the correct answer is option 'B' which is -3V.
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