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A stone of mass m1 moving with a uniform speed v suddenly explodes on its own into two fragments. If the fragment of mass m2 is at rest, the speed of the other fragment is-
- a)
- b)
- c)
- d)
Correct answer is option 'A'. Can you explain this answer?
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Verified Answer
A stone of mass m1moving with a uniform speed v suddenly explodes on i...
As the stone of mass m1 moving with a constant speed, v,
its momentum is m1v.
When it explodes into 2 fragments, we have m2 the fragment, which remains at rest and hence, its momentum is 0.
The mass of other fragment is m1−m2, if its velocity is V, then its momentum is V(m1−m2).
As momentum is conserved, we should have momentum before the split and after the split as equal and therefore
m1v=0+V(m1−m2)
or, V(m1−m2) =m1v
or, V=m1v/m1−m2
its momentum is m1v.
When it explodes into 2 fragments, we have m2 the fragment, which remains at rest and hence, its momentum is 0.
The mass of other fragment is m1−m2, if its velocity is V, then its momentum is V(m1−m2).
As momentum is conserved, we should have momentum before the split and after the split as equal and therefore
m1v=0+V(m1−m2)
or, V(m1−m2) =m1v
or, V=m1v/m1−m2
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A stone of mass m1moving with a uniform speed v suddenly explodes on i...
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A stone of mass m1moving with a uniform speed v suddenly explodes on its own into two fragments. If the fragment of mass m2is at rest, the speed of the other fragment is-a)b)c)d)Correct answer is option 'A'. Can you explain this answer?
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