Each question is followed by two quantities, A and B. Answer each ques...
Let x be the number of 4 rupee coins that Rajesh paid andy be the number of 5 rupee coins that he paid.
4x + 5y - 150... (i)
Dividing (i) by 4 we get;
Now, as x andy are number of coins, they should be integers.
y - 2 = 4p
y = 4p + 2 ...(ii)
Substituting (ii) in (i) we get,
4x + 5(4p + 2) = 150
4x = 150 - 10 - 20p
4x = 140 - 20p
x = 35 - 5p ...(iii)
For p > 7 , x will be negative and for p < 0, y will be negative.
Now for
will be greater than x and for p < 4, y will be less than x.
In no case will y be equal to x.
Probability that x > y = 4/8 = 0.5 and probability that x < y = 4/8 = 0.5.
Hence, both the quantities are equal. Hence, option 3.
Alternatively,
Let x be the number of 4 rupee coins that Rajesh paid and y be the number of 5 rupee coins that he paid.
4x + 5y = 150 ... (i)
5y = 150 - 4x
Since the LHS is a multiple of 5, the RHS has to be divisible by 5. Hence, 4x has to be a multiple of 5.
Hence, x can take 8 values i.e. 0, 5, 10, 15, 20, 25, 30 and 35.
The corresponding values ofy are 30, 36, 22, 18, 14, 10, 6 and 2.
Observe that for the first four values, x <y, and for the last four values, x >y
Probability that x > y = 4/8 = 0.5 and probability that x < y = 4/8 = 0.5.
Hence, both the quantities are equal.
Hence, option 3.