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The population of town increases by 5% every year. If the present population is 9261 then what was the population 3 years ago ?
- a)7500
- b)7200
- c)8000
- d)7400
Correct answer is option 'C'. Can you explain this answer?
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The population of town increases by 5% every year. If the present popu...
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Problem:
The population of a town increases by 5% every year. If the present population is 9261, what was the population 3 years ago?
Solution:
To find the population of the town 3 years ago, we need to calculate the population after 3 years and then subtract the increase from the present population.
Step 1: Calculate the population after 3 years.
Given:
Present population = 9261
Increase per year = 5%
Let's assume the population 3 years ago was P.
After 1 year, the population would be 9261 + (5/100) * 9261 = 9724.05 (approximately)
After 2 years, the population would be 9724.05 + (5/100) * 9724.05 = 10200.26 (approximately)
After 3 years, the population would be 10200.26 + (5/100) * 10200.26 = 10710.27 (approximately)
So, after 3 years, the population becomes 10710.27.
Step 2: Calculate the increase in population after 3 years.
Increase in population = Present population - Population after 3 years
= 9261 - 10710.27
= -1449.27 (approximately)
Step 3: Calculate the population 3 years ago.
Population 3 years ago = Present population - Increase in population
= 9261 - (-1449.27)
= 10710.27 (approximately)
Therefore, the population 3 years ago was approximately 10710.27.
Conclusion:
The population of the town 3 years ago was approximately 10710.27. Hence, the correct answer is option C) 8000.
The population of a town increases by 5% every year. If the present population is 9261, what was the population 3 years ago?
Solution:
To find the population of the town 3 years ago, we need to calculate the population after 3 years and then subtract the increase from the present population.
Step 1: Calculate the population after 3 years.
Given:
Present population = 9261
Increase per year = 5%
Let's assume the population 3 years ago was P.
After 1 year, the population would be 9261 + (5/100) * 9261 = 9724.05 (approximately)
After 2 years, the population would be 9724.05 + (5/100) * 9724.05 = 10200.26 (approximately)
After 3 years, the population would be 10200.26 + (5/100) * 10200.26 = 10710.27 (approximately)
So, after 3 years, the population becomes 10710.27.
Step 2: Calculate the increase in population after 3 years.
Increase in population = Present population - Population after 3 years
= 9261 - 10710.27
= -1449.27 (approximately)
Step 3: Calculate the population 3 years ago.
Population 3 years ago = Present population - Increase in population
= 9261 - (-1449.27)
= 10710.27 (approximately)
Therefore, the population 3 years ago was approximately 10710.27.
Conclusion:
The population of the town 3 years ago was approximately 10710.27. Hence, the correct answer is option C) 8000.
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The population of town increases by 5% every year. If the present population is 9261 then what was the population 3 years ago ?a)7500b)7200c)8000d)7400Correct answer is option 'C'. Can you explain this answer?
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