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25.3 g of sodium carbonate, Na2CO3 is dissolved in enough water to make 250 mL of solution. If sodium carbonate dissociates completely, molar concentration of sodium ions, Na+ and carbonate ions CO2-3  are respectively (Molar mass of Na2CO3 = 106 g mol-1)
  • a)
    0.955 M and 1.910 M
  • b)
    1.910 M and 0.955 M
  • c)
    1.90 M and 1.910M
  • d)
    0.477 M and 0.477 M
Correct answer is option 'B'. Can you explain this answer?
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Calculation:
- Given mass of Na2CO3 = 25.3 g
- Molar mass of Na2CO3 = 106 g/mol
- Number of moles of Na2CO3 = 25.3 g / 106 g/mol = 0.238 moles

Molar concentration of Na+ ions:
- Since Na2CO3 dissociates into 2 Na+ ions, the number of moles of Na+ ions = 2 * 0.238 = 0.476 moles
- Volume of solution = 250 mL = 0.25 L
- Molar concentration of Na+ ions = 0.476 moles / 0.25 L = 1.904 M

Molar concentration of CO2-3 ions:
- Since Na2CO3 dissociates into 1 CO2-3 ion, the number of moles of CO2-3 ions = 0.238 moles
- Molar concentration of CO2-3 ions = 0.238 moles / 0.25 L = 0.952 M
Therefore, the molar concentration of sodium ions (Na+) is 1.904 M and the molar concentration of carbonate ions (CO2-3) is 0.952 M. Hence, option B is the correct answer.
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Direction: Read the passage given below and answer the following questions: Boiling point or freezing point of liquid solution would be affected by the dissolved solids in the liquid phase. A soluble solid in solution has the effect of raising its boiling point and depressing its freezing point. The addition of non-volatile substances to a solvent decreases the vapour pressure and the added solute particles affect the formation of pure solvent crystals. According to many researches the decrease in freezing point directly correlated to the concentration of solutes dissolved in the solvent. This phenomenon is expressed as freezing point depression and it is useful for several applications such as freeze concentration of liquid food and to find the molar mass of an unknown solute in the solution. Freeze concentration is a high quality liquid food concentration method where water is removed by forming ice crystals. This is done by cooling the liquid food below the freezing point of the solution. The freezing point depression is referred as a colligative property and it is proportional to the molar concentration of the solution (m), along with vapour pressure lowering, boiling point elevation, and osmotic pressure. These are physical characteristics of solutions that depend only on the identity of the solvent and the concentration of the solute. The characters are not depending on the solute’s identity. Q.When a non volatile solid is added to pure water it will

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25.3 g of sodium carbonate, Na2CO3 is dissolved in enough water to make 250 mL ofsolution.If sodium carbonate dissociatescompletely, molar concentration of sodium ions, Na+and carbonate ions CO2-3are respectively(Molar mass of Na2CO3 = 106 g mol-1)a)0.955 M and 1.910 Mb)1.910 M and 0.955 Mc)1.90 M and 1.910Md)0.477 M and 0.477 MCorrect answer is option 'B'. Can you explain this answer?
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