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5 gram of unknown solute is dissolved in 295 gram of sorghum if Molarity and density of solution are 0.05 M and 1.5 g/cc respectively then molecular weight of unknown solute is - 1) 375 2)425 3)400 4)500?
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5 gram of unknown solute is dissolved in 295 gram of sorghum if Molari...
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5 gram of unknown solute is dissolved in 295 gram of sorghum if Molari...
Solution:

Given data:
- Mass of solute (unknown) = 5 g
- Mass of sorghum = 295 g
- Molarity of solution = 0.05 M
- Density of solution = 1.5 g/cc

Calculation:
- First, calculate the moles of solute using the formula:
Moles = Molarity x Volume (in L)
Volume = Mass / Density = 295 g / 1.5 g/cc = 196.67 cc = 0.19667 L
Moles = 0.05 x 0.19667 = 0.0098335 mol
- Calculate the molar mass of the solute using the formula:
Molar mass = Mass / Moles
Molar mass = 5 g / 0.0098335 mol = 508.21 g/mol

Answer:
Therefore, the molecular weight of the unknown solute is approximately 508 g/mol. Since the options provided are 375, 425, 400, and 500, the closest option is 500. Hence, the answer is 4) 500.
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5 gram of unknown solute is dissolved in 295 gram of sorghum if Molarity and density of solution are 0.05 M and 1.5 g/cc respectively then molecular weight of unknown solute is - 1) 375 2)425 3)400 4)500?
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5 gram of unknown solute is dissolved in 295 gram of sorghum if Molarity and density of solution are 0.05 M and 1.5 g/cc respectively then molecular weight of unknown solute is - 1) 375 2)425 3)400 4)500? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about 5 gram of unknown solute is dissolved in 295 gram of sorghum if Molarity and density of solution are 0.05 M and 1.5 g/cc respectively then molecular weight of unknown solute is - 1) 375 2)425 3)400 4)500? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for 5 gram of unknown solute is dissolved in 295 gram of sorghum if Molarity and density of solution are 0.05 M and 1.5 g/cc respectively then molecular weight of unknown solute is - 1) 375 2)425 3)400 4)500?.
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