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4.28 g of NaOH is dissolved in water and the solution is made to 250 cc. What will be the molarity of the solution? (a) 0.615 mol L-1 (c) 0.99 mol L-1 (b) 0.428 mol L-1 (d) 0.301 mol L-1?
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4.28 g of NaOH is dissolved in water and the solution is made to 250 c...
Given information:
- Mass of NaOH = 4.28 g
- Volume of solution = 250 cc

To find:
- Molarity of the solution

Formula:
Molarity (M) = Number of moles of solute ÷ Volume of solution in liters

Solution:
1. Calculate the number of moles of NaOH:
- Molar mass of NaOH = 23 + 16 + 1 = 40 g/mol (sum of atomic masses of Na, O, and H)
- Number of moles of NaOH = Mass of NaOH ÷ Molar mass of NaOH
- Number of moles of NaOH = 4.28 g ÷ 40 g/mol
- Number of moles of NaOH = 0.107 mol

2. Convert the volume of solution to liters:
- 250 cc = 250 ÷ 1000 L (1 cc = 1 mL)
- Volume of solution = 0.25 L

3. Calculate the molarity of the solution:
- Molarity (M) = Number of moles of solute ÷ Volume of solution in liters
- Molarity (M) = 0.107 mol ÷ 0.25 L
- Molarity (M) = 0.428 mol/L

Answer:
- The molarity of the solution is 0.428 mol/L.
- Therefore, the correct option is (b) 0.428 mol L-1.
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4.28 g of NaOH is dissolved in water and the solution is made to 250 cc. What will be the molarity of the solution? (a) 0.615 mol L-1 (c) 0.99 mol L-1 (b) 0.428 mol L-1 (d) 0.301 mol L-1?
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4.28 g of NaOH is dissolved in water and the solution is made to 250 cc. What will be the molarity of the solution? (a) 0.615 mol L-1 (c) 0.99 mol L-1 (b) 0.428 mol L-1 (d) 0.301 mol L-1? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about 4.28 g of NaOH is dissolved in water and the solution is made to 250 cc. What will be the molarity of the solution? (a) 0.615 mol L-1 (c) 0.99 mol L-1 (b) 0.428 mol L-1 (d) 0.301 mol L-1? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for 4.28 g of NaOH is dissolved in water and the solution is made to 250 cc. What will be the molarity of the solution? (a) 0.615 mol L-1 (c) 0.99 mol L-1 (b) 0.428 mol L-1 (d) 0.301 mol L-1?.
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