Determining the Molarity of a Solution

To calculate the molarity of a solution, we need to know the number of moles of solute and the volume of the solution. In this case, we are given that 2 grams of NaCO3 (sodium carbonate) is dissolved in 250 mL of solution. We can use this information to determine the molarity.

Step 1: Convert grams to moles

The first step is to convert the mass of the solute (NaCO3) into moles. To do this, we need to know the molar mass of NaCO3, which can be calculated by adding up the atomic masses of each element in the compound.

The molar mass of NaCO3 can be calculated as follows:
Na (sodium) = 23 g/mol
C (carbon) = 12 g/mol
O (oxygen) = 16 g/mol

Molar mass of NaCO3 = (23 g/mol * 1) + (12 g/mol * 1) + (16 g/mol * 3) = 23 g/mol + 12 g/mol + 48 g/mol = 83 g/mol

Now, we can use the molar mass to convert grams to moles:
moles of NaCO3 = 2 g / 83 g/mol = 0.0241 mol

Step 2: Convert mL to L

Next, we need to convert the volume of the solution from milliliters to liters. There are 1000 mL in 1 L, so:
volume of solution = 250 mL / 1000 mL/L = 0.25 L

Step 3: Calculate Molarity

Finally, we can calculate the molarity of the solution using the formula:
Molarity (M) = moles of solute / volume of solution in liters

Molarity = 0.0241 mol / 0.25 L = 0.0964 M

Explanation and Conclusion

In conclusion, the molarity of the solution containing 2 grams of NaCO3 dissolved in 250 mL of solution is 0.0964 M. This means that there are 0.0964 moles of NaCO3 per liter of solution.

To determine the molarity, we first converted the mass of NaCO3 to moles using its molar mass. Then, we converted the volume from milliliters to liters. Finally, we divided the moles of solute by the volume of the solution in liters to obtain the molarity.

It is important to note that the molarity of a solution is a measure of the concentration of the solute. It gives us information about the number of moles of solute present in a given volume of solution.