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The activation energy of a reaction at a given temperature is found to be 2.303 RT J mol–1.The ratio of rate constant to the Arrhenius factor isa)0.1b)0.01c)0.001d)0.02Correct answer is option 'A'. Can you explain this answer? for Class 12 2024 is part of Class 12 preparation. The Question and answers have been prepared according to the Class 12 exam syllabus. Information about The activation energy of a reaction at a given temperature is found to be 2.303 RT J mol–1.The ratio of rate constant to the Arrhenius factor isa)0.1b)0.01c)0.001d)0.02Correct answer is option 'A'. Can you explain this answer? covers all topics & solutions for Class 12 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The activation energy of a reaction at a given temperature is found to be 2.303 RT J mol–1.The ratio of rate constant to the Arrhenius factor isa)0.1b)0.01c)0.001d)0.02Correct answer is option 'A'. Can you explain this answer?.

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