The empty weight of jar is 20% of its weight when it is completely fil...
Problem Statement
The empty weight of a jar is 20% of its weight when it is completely filled with water. If some water is taken out of the jar such that the current weight of the jar is 40% of its weight when it is completely filled with water, what percentage of water is taken out of the jar?
Solution
Let the weight of the jar when it is completely filled with water be 'w' and its empty weight be 'e'.
We know that e = 0.2w
Let the amount of water taken out of the jar be 'x'.
So, the current weight of the jar = (w - x) + e = (w - x) + 0.2w = 0.4w
Simplifying the equation, we get,
0.6w - x = 0.2w
0.4w = x
Therefore, the amount of water taken out of the jar is 0.4w.
Now, the percentage of water taken out of the jar can be calculated as follows:
Percentage of water taken out = (Amount of water taken out / Total capacity of the jar) x 100
= (0.4w / w) x 100
= 40%
Therefore, option (d) 50% is incorrect, and the correct answer is (e) None of these, and the percentage of water taken out of the jar is 40%.
The empty weight of jar is 20% of its weight when it is completely fil...
The answer is 75 percent consider the weight of the jar to be w and the weight of the completely filled jar be 5w with only 40 percent left it is 2w including the weight of jar and removing this we get 75 percent