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A capacitor of capacity 10 μ F is charged to 40V and a second capacitor of capacity 15 μ F is charged to 30V. If they are connected in parallel the amount of charge that flows from the smaller capacitor to higher capacitor in μ C is
  • a)
    30
  • b)
    60
  • c)
    200
  • d)
    250
Correct answer is option 'B'. Can you explain this answer?
Verified Answer
A capacitor of capacity 10 μ F is charged to 40V and a second capac...

Amount of charge flowing = 10 x 40 − 10 x 34 = 60
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Most Upvoted Answer
A capacitor of capacity 10 μ F is charged to 40V and a second capac...

Analysis:
To find the amount of charge that flows from the smaller capacitor to the higher capacitor when they are connected in parallel, we can use the principle of conservation of charge.

Given:
- Capacitance of first capacitor (C1) = 10 μF
- Initial charge on first capacitor (Q1) = C1 * V1 = 10 μF * 40V = 400 μC
- Capacitance of second capacitor (C2) = 15 μF
- Initial charge on second capacitor (Q2) = C2 * V2 = 15 μF * 30V = 450 μC

Calculations:
- When the capacitors are connected in parallel, the total charge remains constant.
- Total charge before connecting = Q1 + Q2 = 400 μC + 450 μC = 850 μC
- Total capacitance after connecting in parallel (C_parallel) = C1 + C2 = 10 μF + 15 μF = 25 μF
- Let the final charge on the capacitors be Q.
- Q = C_parallel * V_f (where V_f is the final voltage)
- Q = 25 μF * V_f

Applying conservation of charge:
- Q = Q1 + Q2
- 25 μF * V_f = 850 μC
- V_f = 850 μC / 25 μF = 34V

Amount of charge that flows from the smaller capacitor to higher capacitor:
- Q_flow = Q2 - Q_f (charge on second capacitor after connecting)
- Q_flow = 450 μC - (15 μF * 34V) = 450 μC - 510 μC = 60 μC

Therefore, the amount of charge that flows from the smaller capacitor to the higher capacitor is 60 μC. Hence, the correct answer is option B.
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A capacitor of capacity 10 μ F is charged to 40V and a second capacitor of capacity 15 μ F is charged to 30V. If they are connected in parallel the amount of charge that flows from the smaller capacitor to higher capacitor in μ C isa)30b)60c)200d)250Correct answer is option 'B'. Can you explain this answer?
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A capacitor of capacity 10 μ F is charged to 40V and a second capacitor of capacity 15 μ F is charged to 30V. If they are connected in parallel the amount of charge that flows from the smaller capacitor to higher capacitor in μ C isa)30b)60c)200d)250Correct answer is option 'B'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about A capacitor of capacity 10 μ F is charged to 40V and a second capacitor of capacity 15 μ F is charged to 30V. If they are connected in parallel the amount of charge that flows from the smaller capacitor to higher capacitor in μ C isa)30b)60c)200d)250Correct answer is option 'B'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A capacitor of capacity 10 μ F is charged to 40V and a second capacitor of capacity 15 μ F is charged to 30V. If they are connected in parallel the amount of charge that flows from the smaller capacitor to higher capacitor in μ C isa)30b)60c)200d)250Correct answer is option 'B'. Can you explain this answer?.
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