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The sum of the digits of a two digit number is 10. If 18 be subtracted from it the digits in the resulting number will be equal. Find the number. a) 37 b) 73 c) 75 d) none of these?
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The sum of the digits of a two digit number is 10. If 18 be subtracted...
Problem: Find a two-digit number whose digits sum up to 10 and upon subtracting 18 from it, the resulting number has equal digits.

Solution:

Let the two-digit number be represented as 10x + y, where x and y are the tens and units digits respectively.

Given, x + y = 10 ---------(1)

Also, 10x + y - 18 = aa (where aa represents the two equal digits)

=> 10x + y = aa + 18 ---------(2)

Subtracting equation (1) from equation (2), we get:

9x = aa + 8 - 10

9x = aa - 2

The only possible values of aa that satisfy this equation are 11 and 20.

Case 1: aa = 11

9x = 9

x = 1

From equation (1), y = 10 - x = 9

Thus, the two-digit number is 19.

Case 2: aa = 20

9x = 18

x = 2

From equation (1), y = 10 - x = 8

Thus, the two-digit number is 28.

Therefore, the possible two-digit numbers are 19 and 28.

Answer: None of these.
Community Answer
The sum of the digits of a two digit number is 10. If 18 be subtracted...
B)
7+3=10
73-18=55
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The sum of the digits of a two digit number is 10. If 18 be subtracted from it the digits in the resulting number will be equal. Find the number. a) 37 b) 73 c) 75 d) none of these?
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