JEE Exam > JEE Questions > A particle A of mass m and charge q is accele...
Start Learning for Free
A particle A of mass 'm' and charge 'q' is accelerated by a potential difference of 50v another particle B of mass '4m' and charge 'q' is accelerated by a potential differnce of 2500V. The ratio of de - Broglie wavelength λA/λB is
Correct answer is '14.14'. Can you explain this answer?
| FREE This question is part of | Download PDF Attempt this Test |
Most Upvoted Answer
A particle A of mass m and charge q is accelerated by a potential diff...
Free Test
FREE
| Start Free Test |
Community Answer
A particle A of mass m and charge q is accelerated by a potential diff...
The de Broglie wavelength of a particle can be determined using the equation:
λ = h / p
where λ is the wavelength, h is the Planck's constant, and p is the momentum of the particle.
The momentum of a particle can be calculated using the equation:
p = mv
where m is the mass of the particle and v is its velocity.
For particle A:
The potential difference is 50V, so the velocity of particle A can be determined using the equation:
qV = 1/2 mv^2
50q = 1/2 mv^2
v^2 = 100q/m
v = √(100q/m)
The momentum of particle A can be calculated as:
p = mv
p = m * √(100q/m)
p = √(100mq)
For particle B:
The potential difference is 2500V, so the velocity of particle B can be determined using the same equation:
qV = 1/2 mv^2
2500q = 1/2 (4m) v^2
5000q = 4mv^2
v^2 = 5000q / 4m
v = √(5000q / 4m)
The momentum of particle B can be calculated as:
p = mv
p = (4m) * √(5000q / 4m)
p = √(5000mq)
Now, the ratio of the de Broglie wavelengths can be calculated as:
λ_A / λ_B = (h / p_A) / (h / p_B)
λ_A / λ_B = p_B / p_A
λ_A / λ_B = √(5000mq) / √(100mq)
λ_A / λ_B = √(50)
Therefore, the ratio of the de Broglie wavelengths of particle A to particle B is √(50) or approximately 7.071.
λ = h / p
where λ is the wavelength, h is the Planck's constant, and p is the momentum of the particle.
The momentum of a particle can be calculated using the equation:
p = mv
where m is the mass of the particle and v is its velocity.
For particle A:
The potential difference is 50V, so the velocity of particle A can be determined using the equation:
qV = 1/2 mv^2
50q = 1/2 mv^2
v^2 = 100q/m
v = √(100q/m)
The momentum of particle A can be calculated as:
p = mv
p = m * √(100q/m)
p = √(100mq)
For particle B:
The potential difference is 2500V, so the velocity of particle B can be determined using the same equation:
qV = 1/2 mv^2
2500q = 1/2 (4m) v^2
5000q = 4mv^2
v^2 = 5000q / 4m
v = √(5000q / 4m)
The momentum of particle B can be calculated as:
p = mv
p = (4m) * √(5000q / 4m)
p = √(5000mq)
Now, the ratio of the de Broglie wavelengths can be calculated as:
λ_A / λ_B = (h / p_A) / (h / p_B)
λ_A / λ_B = p_B / p_A
λ_A / λ_B = √(5000mq) / √(100mq)
λ_A / λ_B = √(50)
Therefore, the ratio of the de Broglie wavelengths of particle A to particle B is √(50) or approximately 7.071.
Attention JEE Students!
To make sure you are not studying endlessly, EduRev has designed JEE study material, with Structured Courses, Videos, & Test Series. Plus get personalized analysis, doubt solving and improvement plans to achieve a great score in JEE.
|
Explore Courses for JEE exam
|
|
Similar JEE Doubts
Top Courses for JEEView all
A particle A of mass m and charge q is accelerated by a potential difference of 50v another particle B of mass 4m and charge q is accelerated by a potential differnce of 2500V. The ratio of de - Broglie wavelengthλA/λBisCorrect answer is '14.14'. Can you explain this answer?
Question Description
A particle A of mass m and charge q is accelerated by a potential difference of 50v another particle B of mass 4m and charge q is accelerated by a potential differnce of 2500V. The ratio of de - Broglie wavelengthλA/λBisCorrect answer is '14.14'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about A particle A of mass m and charge q is accelerated by a potential difference of 50v another particle B of mass 4m and charge q is accelerated by a potential differnce of 2500V. The ratio of de - Broglie wavelengthλA/λBisCorrect answer is '14.14'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A particle A of mass m and charge q is accelerated by a potential difference of 50v another particle B of mass 4m and charge q is accelerated by a potential differnce of 2500V. The ratio of de - Broglie wavelengthλA/λBisCorrect answer is '14.14'. Can you explain this answer?.
A particle A of mass m and charge q is accelerated by a potential difference of 50v another particle B of mass 4m and charge q is accelerated by a potential differnce of 2500V. The ratio of de - Broglie wavelengthλA/λBisCorrect answer is '14.14'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about A particle A of mass m and charge q is accelerated by a potential difference of 50v another particle B of mass 4m and charge q is accelerated by a potential differnce of 2500V. The ratio of de - Broglie wavelengthλA/λBisCorrect answer is '14.14'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A particle A of mass m and charge q is accelerated by a potential difference of 50v another particle B of mass 4m and charge q is accelerated by a potential differnce of 2500V. The ratio of de - Broglie wavelengthλA/λBisCorrect answer is '14.14'. Can you explain this answer?.
Solutions for A particle A of mass m and charge q is accelerated by a potential difference of 50v another particle B of mass 4m and charge q is accelerated by a potential differnce of 2500V. The ratio of de - Broglie wavelengthλA/λBisCorrect answer is '14.14'. Can you explain this answer? in English & in Hindi are available as part of our courses for JEE.
Download more important topics, notes, lectures and mock test series for JEE Exam by signing up for free.
Here you can find the meaning of A particle A of mass m and charge q is accelerated by a potential difference of 50v another particle B of mass 4m and charge q is accelerated by a potential differnce of 2500V. The ratio of de - Broglie wavelengthλA/λBisCorrect answer is '14.14'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of
A particle A of mass m and charge q is accelerated by a potential difference of 50v another particle B of mass 4m and charge q is accelerated by a potential differnce of 2500V. The ratio of de - Broglie wavelengthλA/λBisCorrect answer is '14.14'. Can you explain this answer?, a detailed solution for A particle A of mass m and charge q is accelerated by a potential difference of 50v another particle B of mass 4m and charge q is accelerated by a potential differnce of 2500V. The ratio of de - Broglie wavelengthλA/λBisCorrect answer is '14.14'. Can you explain this answer? has been provided alongside types of A particle A of mass m and charge q is accelerated by a potential difference of 50v another particle B of mass 4m and charge q is accelerated by a potential differnce of 2500V. The ratio of de - Broglie wavelengthλA/λBisCorrect answer is '14.14'. Can you explain this answer? theory, EduRev gives you an
ample number of questions to practice A particle A of mass m and charge q is accelerated by a potential difference of 50v another particle B of mass 4m and charge q is accelerated by a potential differnce of 2500V. The ratio of de - Broglie wavelengthλA/λBisCorrect answer is '14.14'. Can you explain this answer? tests, examples and also practice JEE tests.
|
|
Explore Courses for JEE exam
|
|
Suggested Free Tests
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
|
© EduRev
|
Education Revolution
|
|
Signup to see your scores
go up within 7 days!
Access 1000+ FREE Docs, Videos and Tests
Takes less than 10 seconds to signup