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 An electron of mass m when accelerated through a potential difference V has de-Broglie wavelength λ. The de-Broglie wavelength associated with a proton of mass M accelerated through the same potential difference will be [CBSE PMT 1995; EAMCET 2001; J & K CET 2004]
  • a)
     λm/M
  • b)
     λ√(m/M)
  • c)
     λM/m
  • d)
     λ√(M/m)
Correct answer is option 'B'. Can you explain this answer?
Most Upvoted Answer
An electron of mass m when accelerated through a potential difference ...
Correct option is
B
As we knwo,
   ( 
= same)
so,
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Community Answer
An electron of mass m when accelerated through a potential difference ...
The de-Broglie wavelength (λ) of a particle is given by the equation:

λ = h / p

where h is the Planck's constant and p is the momentum of the particle. The momentum of an electron can be calculated using the equation:

p = √(2mV)

where m is the mass of the electron and V is the potential difference.

Substituting the value of p in the equation for the de-Broglie wavelength, we get:

λ = h / √(2mV)
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An electron of mass m when accelerated through a potential difference V has de-Broglie wavelengthλ. The de-Broglie wavelength associated with a proton of mass M accelerated through the same potential difference will be [CBSE PMT 1995; EAMCET 2001; J & K CET 2004]a)λm/Mb)λ√(m/M)c)λM/md)λ√(M/m)Correct answer is option 'B'. Can you explain this answer?
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An electron of mass m when accelerated through a potential difference V has de-Broglie wavelengthλ. The de-Broglie wavelength associated with a proton of mass M accelerated through the same potential difference will be [CBSE PMT 1995; EAMCET 2001; J & K CET 2004]a)λm/Mb)λ√(m/M)c)λM/md)λ√(M/m)Correct answer is option 'B'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about An electron of mass m when accelerated through a potential difference V has de-Broglie wavelengthλ. The de-Broglie wavelength associated with a proton of mass M accelerated through the same potential difference will be [CBSE PMT 1995; EAMCET 2001; J & K CET 2004]a)λm/Mb)λ√(m/M)c)λM/md)λ√(M/m)Correct answer is option 'B'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for An electron of mass m when accelerated through a potential difference V has de-Broglie wavelengthλ. The de-Broglie wavelength associated with a proton of mass M accelerated through the same potential difference will be [CBSE PMT 1995; EAMCET 2001; J & K CET 2004]a)λm/Mb)λ√(m/M)c)λM/md)λ√(M/m)Correct answer is option 'B'. Can you explain this answer?.
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