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A circular shaft subjected to twisting moment results in maximum shear stress of 60 MPa. Then the maximum compressive stress in the material is
- a)30 MPa
- b)60 MPa
- c)90 MPa
- d)120 MPa
Correct answer is option 'B'. Can you explain this answer?
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Most Upvoted Answer
A circular shaft subjected to twisting moment results in maximum shear...
**Explanation:**
When a circular shaft is subjected to a twisting moment, it experiences shear stress due to the torsional force. The maximum shear stress occurs at the outer surface of the shaft.
To calculate the maximum compressive stress in the material, we can use the maximum shear stress formula for a circular shaft:
**Maximum Shear Stress (τmax) = T * r / J**
Where:
- τmax is the maximum shear stress
- T is the twisting moment
- r is the radius of the shaft
- J is the polar moment of inertia of the shaft cross-section
In this case, we are given that the maximum shear stress is 60 MPa. Let's assume the twisting moment is T and the radius of the shaft is r.
Therefore, we have:
**60 MPa = T * r / J**
To find the maximum compressive stress, we need to relate it to the maximum shear stress.
The maximum compressive stress (σc) occurs at the inner surface of the shaft and is related to the maximum shear stress (τmax) by the following relation:
**σc = τmax / 2**
Substituting the given value of maximum shear stress (60 MPa) into the above equation, we get:
**σc = 60 MPa / 2 = 30 MPa**
Therefore, the maximum compressive stress in the material is 30 MPa, which corresponds to option B.
When a circular shaft is subjected to a twisting moment, it experiences shear stress due to the torsional force. The maximum shear stress occurs at the outer surface of the shaft.
To calculate the maximum compressive stress in the material, we can use the maximum shear stress formula for a circular shaft:
**Maximum Shear Stress (τmax) = T * r / J**
Where:
- τmax is the maximum shear stress
- T is the twisting moment
- r is the radius of the shaft
- J is the polar moment of inertia of the shaft cross-section
In this case, we are given that the maximum shear stress is 60 MPa. Let's assume the twisting moment is T and the radius of the shaft is r.
Therefore, we have:
**60 MPa = T * r / J**
To find the maximum compressive stress, we need to relate it to the maximum shear stress.
The maximum compressive stress (σc) occurs at the inner surface of the shaft and is related to the maximum shear stress (τmax) by the following relation:
**σc = τmax / 2**
Substituting the given value of maximum shear stress (60 MPa) into the above equation, we get:
**σc = 60 MPa / 2 = 30 MPa**
Therefore, the maximum compressive stress in the material is 30 MPa, which corresponds to option B.
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Community Answer
A circular shaft subjected to twisting moment results in maximum shear...
Answer B is correct
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A circular shaft subjected to twisting moment results in maximum shear stress of 60 MPa. Then the maximum compressive stress in the material isa)30 MPab)60 MPac)90 MPad)120 MPaCorrect answer is option 'B'. Can you explain this answer?
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