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The mutual inductance of an induction coil is 5 H. In the primary coil, the current reduces from 5 A to zero in 10-3s. What is the induced emf in the secondary coil ?
  • a)
    2500 V
  • b)
    25000 V
  • c)
    2510 V
  • d)
    Zero
Correct answer is option 'B'. Can you explain this answer?
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The mutual inductance of an induction coil is 5 H. In the primary coil...
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The mutual inductance of an induction coil is 5 H. In the primary coil...
Given:
Mutual inductance (M) = 5 H
Current in primary coil (I1) = 5 A
Time taken for current to reduce to zero (t) = 10^-3 s

To find:
Induced emf in the secondary coil (E2)

Formula:
The induced emf in the secondary coil is given by the formula:
E2 = -M(dI1/dt)

where, dI1/dt is the rate of change of current in the primary coil.

Calculation:
dI1/dt = (5 - 0)/10^-3 = 5000 A/s

Using the formula, we get:
E2 = -5 × 5000 = -25000 V

Since the negative sign indicates the direction of the induced emf, the magnitude of the induced emf in the secondary coil is 25000 V.

Therefore, the correct answer is option B) 25000 V.
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