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Raman dropped a crystal of copper sulphate in beaker A and B contain cold and hot water 1. Write the colour of the solution in the both case 2. In which beaker the colour change took place faster rate?
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Raman dropped a crystal of copper sulphate in beaker A and B contain c...
Answer:

Color of the solution in both cases:


  • Beaker A (cold water): The crystal of copper sulphate dissolves slowly in cold water, and the solution is light blue in color.

  • Beaker B (hot water): The crystal of copper sulphate dissolves quickly in hot water, and the solution is dark blue in color.



Explanation of the color change rate:


  • The rate of dissolution of copper sulphate in water depends on the temperature of the water. The higher the temperature, the faster the crystal dissolves.

  • When copper sulphate is dropped into the cold water, the crystal dissolves slowly, and the light blue color of the solution takes time to develop.

  • On the other hand, when copper sulphate is dropped into the hot water, the crystal dissolves quickly, and the dark blue color of the solution develops at a faster rate.

  • Thus, the color change takes place at a faster rate in beaker B (hot water) as compared to beaker A (cold water).

Community Answer
Raman dropped a crystal of copper sulphate in beaker A and B contain c...
The color of the solution in beaker A will be dark blue and in the beaker B the color will be light blue. In beaker A the color change took place faster rate due fast diffusion.Greater the temperature more will be diffusion, so the beaker A will show faster rate of change in color because of greater temperature.
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Raman dropped a crystal of copper sulphate in beaker A and B contain cold and hot water 1. Write the colour of the solution in the both case 2. In which beaker the colour change took place faster rate?
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