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A quadratic polynomial ax2 + bx + c = 0 is such that when it is divided by x, (x - 1) and (x + 1), the remainders are 3, 6 and 4 respectively. What is the value of (a + b)?
  • a)
    3
  • b)
    2
  • c)
    1
  • d)
    -1
Correct answer is option 'A'. Can you explain this answer?
Verified Answer
A quadratic polynomial ax2+ bx + c = 0 is such that when it is divided...
ax2 + bx + c = x (ax + b) + c
Remainder when divided by x = c
∴ c = 3
Let P(x) be a polynomial when divided by (x - a), then the remainder is P(a)
Remainder when divided by (x - 1) = P(1)
6 = a (1) + b(1) + c
6 = a + b + 3
∴ a + b = 3
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Most Upvoted Answer
A quadratic polynomial ax2+ bx + c = 0 is such that when it is divided...

Given information:

- Quadratic polynomial: ax^2 + bx + c = 0
- Remainders when divided by x, (x - 1), and (x + 1) are 3, 6, and 4 respectively

Calculating the Remainders:

- When the polynomial is divided by x, the remainder is 3
- This means that when x = 0, the polynomial evaluates to 3
- Hence, c = 3

- When the polynomial is divided by (x - 1), the remainder is 6
- This means that when x = 1, the polynomial evaluates to 6
- Substituting x = 1 in the polynomial, we get: a(1)^2 + b(1) + 3 = 6
- This simplifies to: a + b = 3

- When the polynomial is divided by (x + 1), the remainder is 4
- This means that when x = -1, the polynomial evaluates to 4
- Substituting x = -1 in the polynomial, we get: a(-1)^2 + b(-1) + 3 = 4
- This simplifies to: a - b = 1

Finding the Value of (a + b):

- Adding the equations a + b = 3 and a - b = 1, we get:
- 2a = 4
- a = 2

- Substituting the value of a in a + b = 3, we get:
- 2 + b = 3
- b = 1

- Therefore, the value of (a + b) = 2 + 1 = 3

Therefore, the correct answer is option A) 3.
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